Answer:
Volume = 29400 cm³
Mass = 21.6 g
Explanation:
Given data:
Number of moles of water vapors = 1.2 mol
Mass of water vapor = ?
Volume of water vapors = ?
Solution:
Room temperature = 25 °C (25+273 = 298 K)
Room pressure = 1 atm
PV = nRT
V = nRT/P
V = 1.2 mol × 0.0821 atm. K⁻¹. mol⁻¹ . L × 298 K/ 1 atm
V = 29.4 L
In cm³:
29.4 × 1000 = 29400 mL
mL = cm³
Mass of water vapors:
<em>Mass = number of moles × molar mass</em>
Mass = 1.2 mol × 18 g/mol
Mass = 21.6 g
Answer:
X represents London dispersion forces, and Y represents dipole-dipole forces.
Explanation:
Answer:Displacement method
Explanation:
Answer:
Specific rotation of cholesterol is -3.15°.
Explanation:
Given that
Path length = 10 cm = 1 dm.
Observed rotation ,α= - 0.441 °
m= 0.14 g
V= 1 ml
The concentration of cholesterol ,c= m/V g/ml
c = 0.14 / 1 = 0.14 g/ml
We know that specific rotation given as
![[\alpha]_D=\dfrac{\alpha}{l.c}](https://tex.z-dn.net/?f=%5B%5Calpha%5D_D%3D%5Cdfrac%7B%5Calpha%7D%7Bl.c%7D)
Now by putting the all values
![[\alpha]_D=\dfrac{-0.441}{1\times 0.14}](https://tex.z-dn.net/?f=%5B%5Calpha%5D_D%3D%5Cdfrac%7B-0.441%7D%7B1%5Ctimes%200.14%7D)
![[\alpha]_D=-3.15](https://tex.z-dn.net/?f=%5B%5Calpha%5D_D%3D-3.15)
°
Specific rotation of cholesterol is -3.15°.
