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elena55 [62]
3 years ago
9

(06.01 MC)

Physics
2 answers:
Misha Larkins [42]3 years ago
8 0

Answer: C. Both observation 1 and observation 2

Explanation: A geocentric model shows the stars and the sun and where they move to.

God bless. <3

professor190 [17]3 years ago
4 0
C. Because the sun rises and sets and the stars move daily across the sky
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How does energy change as it moves through the ecosystem?
Galina-37 [17]

Answer:

by the animeals and himens getting vood

Explanation:

3 0
3 years ago
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A car increased its velocity to 62m/s in 10s starting from rest. Calculate the distance it covers during this time?
Roman55 [17]

Answer:

distance= velocity ×time

distance= 62×10

distance=620m

hope it helps you mate please mark me as brainliast

6 0
3 years ago
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The gravitational force between two objects that
leonid [27]

Answer:

The answer to your question is    m₂ = 38.5 kg

Explanation:

Data

distance = d = 2.1 x 10⁻¹ m

Force = 3.2 x 10⁻⁶ N

m₁ = 55 kg

m₂ = ?

G = 6.67 x 10 ⁻¹¹ Nm²/kg²

Process

1.- To solve this problem use Newton's law of Universal Gravitation.

             F = G m₁m₂ / r²

-Solve for m₂

            m₂ = Fr² / Gm₁

2.- Substitution

            m₂ = (3.2 x 10⁻⁶)(2.1 x 10⁻¹)² / (6.67 x 10⁻¹¹)(55)

3.- Simplification

            m₂ = 1.411 x 10⁻⁷ / 3.669 x 10⁻⁹

4.- Result

            m₂ = 38.5 kg

5 0
3 years ago
Which statement is correct?
slega [8]

Answer:B

Explanation:

Galilean transformation are only approximately correct,while Lorentz transformation are more exact

6 0
3 years ago
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Calculate the acceleration of a 1000 kg car if the motor provides a small thrust of 1000 N and the static and dynamic friction c
grin007 [14]

Explanation :

It is given that,

Mass of the car, m = 1000 kg              

Force applied by the motor, F_A=1000\ N

The static and dynamic friction coefficient is, \mu=0.5

Let a is the acceleration of the car. Since, the car is in motion, the coefficient of sliding friction can be used. At equilibrium,

F_A-\mu mg=ma

\dfrac{F_A-\mu mg}{m}=a

a=\dfrac{1000-0.5(1000)(9.81)}{1000}

a=-3.905\ m/s^2

So, the acceleration of the car is -3.905\ m/s^2. Hence, this is the required solution.

6 0
3 years ago
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