Answer:
Technician A is right. The situation will happens even with only two bulbs in series
Explanation:
We must take into account that
1.- All electric device need its nominal voltage to operate
2.-Any and all electric device means an electric load for the source in terms of equation that means any device will implies a drop voltage of V = I*R ( I the flows current and R the resistance of the device)
3.-Nominal voltage for bulbs are specify for houses voltages you find between fase and neutral wires for instance in Venezuela 120 (v).
4.-In a imaginary circuit of only one bulb, the nominal voltage will be applied and the bulb will operates correctly, but when you add another bulb (in series) the nominal voltage will split between the two bulbs ( we could find a situation such as the first bulb work properly but the second one does not). The voltage split according to Ohms law (in such way that the sum of voltage between the terminal of the first bulb plus the voltage at terminals of the second one are equal to nominal voltage.
For that reason all the bulbs are connected in parallel in wich case all of them will operate with the common voltage
<u>Answer:</u>
The acceleration of the car is 
<u>Explanation:</u>
In the question it is given that car initially heads north with a velocity
. It then accelerates for
and in the end its velocity is
.
initial velocity 
time 
final velocity 
The equation of acceleration is


The value of acceleration is positive, here since the car is speeding up. If it was slowing down the value of acceleration would be negative.
Each electron holds 2(n2)
Answer: The two answers are in explanation.
Explanation: Please find the attached files for the solution
Answers and Explanation:
The step by step explanation is clearly screenshot in the two attachments below for easy understanding.
NOTE:
A uniform charged solid sphere of radius R carries a total charge Q, it therefore has its charge density as Q/(4/3ΠR³). And to find magnetic moment of a sphere, the sphere has to be divided into infinitesimal charges.
Magnetic Dipole Moment of the sphere would be given as 1/5QwR²z
(Check attachments below for clarity)