1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Liono4ka [1.6K]
3 years ago
9

What were the three factors that affected density

Physics
1 answer:
Stolb23 [73]3 years ago
7 0

Answer:

Pressure, temperature and humidity all affect air density. And you can think of air density as the mass of air molecules in a given volume.

Explanation:

You might be interested in
what were the negative results with the american television from analog broadcast to digital broadcast?
alexandr1967 [171]

Answer:

Explanation:

everything

8 0
3 years ago
Read 2 more answers
When buying a car, you tell the salesman that you want to make sure the car can go from 0 miles per hour to 60 miles per hour in
MaRussiya [10]
Acceleration....................................... <span />
4 0
3 years ago
Read 2 more answers
An 100 kg object traveling at 50 m/s collides (perfectly inelastic) with a 50 kg object initially at rest.
qaws [65]

Answer:

Option C. 5,000 kg m/s

Explanation:

<u>Linear Momentum on a System of Particles </u>

Is defined as the sum of the momenta of each particles in a determined moment. The individual momentum is the product of the mass of the particle by its speed

P=mv

The question refers to an 100 kg object traveling at 50 m/s who collides with another object of 50 kg object initially at rest. We compute the moments of each object

m_1=(100\ kg)(50\ m/s)=5,000\ kg\ m/s

m_2=(50\ kg)(0\ m/s) = 0

The sum of the momenta of both objects prior to the collision is

P=5,000\ kg\ m/s+0\ kg\ m/s

\boxed{ P=5,000\ kg\ m/s}

7 0
3 years ago
Four equal masses m are so small they can be treated as points, and they are equallyspaced along a long, stiff mass less wire. T
gavmur [86]

The moment of inertia of a point mass about an arbitrary point is given by:

I = mr²

I is the moment of inertia

m is the mass

r is the distance between the arbitrary point and the point mass

The center of mass of the system is located halfway between the 2 inner masses, therefore two masses lie ℓ/2 away from the center and the outer two masses lie 3ℓ/2 away from the center.

The total moment of inertia of the system is the sum of the moments of each mass, i.e.

I = ∑mr²

The moment of inertia of each of the two inner masses is

I = m(ℓ/2)² = mℓ²/4

The moment of inertia of each of the two outer masses is

I = m(3ℓ/2)² = 9mℓ²/4

The total moment of inertia of the system is

I = 2[mℓ²/4]+2[9mℓ²/4]

I = mℓ²/2+9mℓ²/2

I = 10mℓ²/2

I = 5mℓ²

4 0
3 years ago
(a) If a proton with a kinetic energy of 6.2 MeV is traveling in a particle accelerator in a circular orbit with a radius of 0.5
Tju [1.3M]

Answer:

The fraction of its energy that it radiates every second is 3.02\times10^{-11}.

Explanation:

Suppose Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by

\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}

Given that,

Kinetic energy = 6.2 MeV

Radius = 0.500 m

We need to calculate the acceleration

Using formula of acceleration

a=\dfrac{v^2}{r}

Put the value into the formula

a=\dfrac{\dfrac{1}{2}mv^2}{\dfrac{1}{2}mr}

Put the value into the formula

a=\dfrac{6.2\times10^{6}\times1.6\times10^{-19}}{\dfrac{1}{2}\times1.67\times10^{-27}\times0.51}

a=2.32\times10^{15}\ m/s^2

We need to calculate the rate at which it emits energy because of its acceleration is

\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}

Put the value into the formula

\dfrac{dE}{dt}=\dfrac{(1.6\times10^{-19})^2\times(2.3\times10^{15})^2}{6\pi\times8.85\times10^{-12}\times(3\times10^{8})^3}

\dfrac{dE}{dt}=3.00\times10^{-23}\ J/s

The energy in ev/s

\dfrac{dE}{dt}=\dfrac{3.00\times10^{-23}}{1.6\times10^{-19}}\ J/s

\dfrac{dE}{dt}=1.875\times10^{-4}\ ev/s

We need to calculate the fraction of its energy that it radiates every second

\dfrac{\dfrac{dE}{dt}}{E}=\dfrac{1.875\times10^{-4}}{6.2\times10^{6}}

\dfrac{\dfrac{dE}{dt}}{E}=3.02\times10^{-11}

Hence, The fraction of its energy that it radiates every second is 3.02\times10^{-11}.

5 0
3 years ago
Other questions:
  • Which point on the pendulum's swing represents the minimum potential energy?
    13·2 answers
  • Heating effect of current is not always useful for us. Support your answer with example<br>​
    6·1 answer
  • As a result of fringing effect :
    11·1 answer
  • A person pushes horizontally with a force of 220. N on a 61.0 kg crate to move it across a level floor. The coefficient of kinet
    6·1 answer
  • In a mixture, the ingredients intermingle and
    10·1 answer
  • What is the gravitational force between mars and Phobos
    9·1 answer
  • Which event is an example of melting?
    15·1 answer
  • A system consists of a copper tank whose mass is 13 kg, 4 kg of liquid water, and an electrical resistor of negligible mass. The
    8·1 answer
  • Find the weight of an object of mass 5 kg
    5·2 answers
  • Can sugar molecules produced from photosynthesis be rearranged into different compounds carry out life process
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!