The mass of an object always stays the same since it is really just the amount of matter in an object so no matter the force applied, as long as the object does not lose or gain matter, the object stays the same
Mount. everest is 5.499 miles
For the front glass of the car to get wet, 
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The given parameters:
- <em>Speed of the car, = Vc</em>
- <em>Speed of the rain, = 10 m/s</em>
The relative velocity of the car with respect to the falling rain is calculated as;
- If the speed of the car equals the speed of the rain, the rain will fall behind the car.
- If the speed of the rain is greater than speed of the car, the rain will fall far in front of the car.
- If the speed of the car is greater than speed of the rain, the rain will fall on the car.
Thus, for the front glass of the car to get wet, .
Learn more about relative velocity here: brainly.com/question/17228388
The equation to be used here is the trajectory of a projectile as written below:
y = xtanθ +/- gx²/2v²(cosθ)²
where
y is the vertical distance
x is the horizontal distance
θ is the angle of trajectory or launch angle
g is 9.81 m/s²
v is the initial velcity
Since the angle is below horizontal, let's use the minus equation. Substituting the values:
- 0.8 m = xtan15° - (9.81 m/s²)x²/2(4.8 m/s)²(cos15°)²
Solving for x,
x = 2.549 m
However, we only take half of this distance because it was specified that the distance asked before bouncing. Hence, the horizontal distance is equal to 1.27 m.
Use ideal gas equation, with T constant.
pV =nRT => pV / n = RT = constant
n = K* [units of particles]
pV / [units of particles] = constant
13 psi * 160 mL / 15 units = p * 150 mL / 10 units =>
=> p = [13psi*160mL/15units]*[10units/150mL] = 9.2 psi
