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3 years ago

What were the three factors that affected density

Physics

1 answer:

Stolb23 [73]3 years ago

7 0

Answer:

Pressure, temperature and humidity all affect air density. And you can think of air density as the mass of air molecules in a given volume.

Explanation:

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what were the negative results with the american television from analog broadcast to digital broadcast?

alexandr1967 [171]

Answer:

Explanation:

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3 years ago

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When buying a car, you tell the salesman that you want to make sure the car can go from 0 miles per hour to 60 miles per hour in

MaRussiya [10]

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3 years ago

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An 100 kg object traveling at 50 m/s collides (perfectly inelastic) with a 50 kg object initially at rest.

qaws [65]

Answer:

Option C. 5,000 kg m/s

Explanation:

<u>Linear Momentum on a System of Particles </u>

Is defined as the sum of the momenta of each particles in a determined moment. The individual momentum is the product of the mass of the particle by its speed

P=mv

The question refers to an 100 kg object traveling at 50 m/s who collides with another object of 50 kg object initially at rest. We compute the moments of each object

$m_1=(100\ kg)(50\ m/s)=5,000\ kg\ m/s$

$m_2=(50\ kg)(0\ m/s) = 0$

The sum of the momenta of both objects prior to the collision is

$P=5,000\ kg\ m/s+0\ kg\ m/s$

$\boxed{ P=5,000\ kg\ m/s}$

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3 years ago

Four equal masses m are so small they can be treated as points, and they are equallyspaced along a long, stiff mass less wire. T

gavmur [86]

The moment of inertia of a point mass about an arbitrary point is given by:

I = mr²

I is the moment of inertia

m is the mass

r is the distance between the arbitrary point and the point mass

The center of mass of the system is located halfway between the 2 inner masses, therefore two masses lie ℓ/2 away from the center and the outer two masses lie 3ℓ/2 away from the center.

The total moment of inertia of the system is the sum of the moments of each mass, i.e.

I = ∑mr²

The moment of inertia of each of the two inner masses is

I = m(ℓ/2)² = mℓ²/4

The moment of inertia of each of the two outer masses is

I = m(3ℓ/2)² = 9mℓ²/4

The total moment of inertia of the system is

I = 2[mℓ²/4]+2[9mℓ²/4]

I = mℓ²/2+9mℓ²/2

I = 10mℓ²/2

I = 5mℓ²

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3 years ago

(a) If a proton with a kinetic energy of 6.2 MeV is traveling in a particle accelerator in a circular orbit with a radius of 0.5

Tju [1.3M]

Answer:

The fraction of its energy that it radiates every second is $3.02\times10^{-11}$ .

Explanation:

Suppose Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by

$\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}$