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ruslelena [56]
3 years ago
8

A cannonball is fired perfectly horizontally from the top of a 210 m tall cliff. It is fired with an initial velocity of 50 m/s.

What is the horizontal distance covered by the cannonball before it hits the ground?
Physics
1 answer:
pochemuha3 years ago
8 0

Answer:

the horizontal distance covered by the cannonball before it hits the ground is 327.5 m

Explanation:

Given;

height of the cliff, h = 210 m

initial horizontal velocity of the cannonball, Ux = 50 m/s

initial vertical velocity of the cannonball, Uy = 0

The time for the cannonball to reach the ground is calculated as;

h = u_yt - \frac{1}{2} gt^2\\\\h = 0 - \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 210}{9.8} }\\\\t  = 6.55 \ s

The horizontal distance covered by the cannonball before it hits the ground is calculated as;

X = U_x \times \ t\\\\X = 50 \times \ 6.55\\\\X = 327.5 \ m

Therefore, the horizontal distance covered by the cannonball before it hits the ground is 327.5 m

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David rowed a boat upstream for three miles and then returned to point he started from. The entire journey took four hours. The
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Two diverging light rays, originating from the same point, have an angle of 5° between them. After the rays reflect from a plane
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The ray on the left leaves the point traveling 5° to the left of the normal,
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valentina_108 [34]

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density

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brainly.com/question/12982373

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