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Sonja [21]
3 years ago
14

Help,very easy question but i can't understand​

Mathematics
2 answers:
ella [17]3 years ago
8 0

Answer:

10

Step-by-step explanation:

10 is the greatest common factor that you can divide into both 40 and 50.

Anna11 [10]3 years ago
4 0

Answer:

10

Step-by-step explanation:

Try and find the prime factorization of 40 and 50.

40=2*2*2*5

50=2*5*5

Multiply the prime  factors that are common to both numbers.

2*5=10

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-2a-9=6a+15<br> Idk how to this equation could someone plzz consider helping me?
ollegr [7]

-2a-9=6a+15

Move 6a to the other side. Sign changs from +6a to -6a.

-2a-6a-9=6a-6a+15

-2a-6a-9=15

-8a-9=15

Move -9 to the other side. Sign changes from -9 to +9.

-8a-9+9=15+9

-8a=15+9

-8a=24

Divide both sides by -8

-8a/-8=24/-8

a=-3

Answer: a=-3

8 0
3 years ago
What si the soulution of 2/3 a - 1/6 = 1/3
11Alexandr11 [23.1K]

Answer:

3/4

Step-by-step explanation:

2/3a-1/6=1/3

2/3a=1/3+1/6

2/3a=3/6

2/3a=1/2

a=1/2X3/2

a=3/4

6 0
3 years ago
Help me answer this question please
Stella [2.4K]

ANSWER

{f}^{ - 1}  =\pm \sqrt{x + 1}

EXPLANATION

The given function is

f(x) =  {x}^{2}  - 1

Let

y =  {x}^{2}  - 1

Interchange x and y to get:

x=  {y}^{2}  - 1

Solve for y,

x + 1 =  {y}^{2}

Take square root of both sides to get,

\pm \sqrt{x + 1}  = y

This is the same as:

y =  \pm \sqrt{x + 1}

Therefore the inverse is

{f}^{ - 1}  =\pm \sqrt{x + 1}

3 0
3 years ago
Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a dilation
Talja [164]
Correct answer is B.
4 0
3 years ago
COSO ---
Vsevolod [243]

Answer:

• zero: -4, -4/3, 7

• positive: -4 < x < -4/3 . . . or 7 < x

• negative: x < -4 . . . or -4/3 < x < 7

Step-by-step explanation:

Zeros of the function are at x=-4, -4/3, +7. These are the values that make each of the individual factors be zero. For example, x-7=0 when x=7.

The function will be negative for x-values left of an odd number of zeros. It will be positive for x-values left of an even number of zeros (including left of no zeros, which is to say right of all zeros). This is because the sign of the factor giving rise to the zero changes for x-values on either side of that zero. (This is not true for zeros with even multiplicity, as the sign does not change at those.)

3 0
3 years ago
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