Answer:
NASA's Chandra X-ray Observatory and other telescopes such as the Hubble telescope.
Explanation:
Dark matter and normal matter have been wrenched apart by the tremendous collision of two large clusters of galaxies.
The above observations have provided the strongest evidence yet that most of the matter in the universe is dark.
A becuz its at da it dont got no wa
Answer:
a) 0.0007326
b) 0.03223
c) 0.2418
d) 0.2418
Explanation:
To find different probabilities for the selection of components among eleven good and four defective components, we will use the Combination.
a) ![C(4,4) = 1; C(15,4) = 1365](https://tex.z-dn.net/?f=C%284%2C4%29%20%3D%201%3B%20C%2815%2C4%29%20%3D%201365)
![P = \frac{C(4,4)}{C(15,4)} = \frac{1}{1365} = 0.0007326](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7BC%284%2C4%29%7D%7BC%2815%2C4%29%7D%20%3D%20%5Cfrac%7B1%7D%7B1365%7D%20%3D%200.0007326)
b) ![C(4,3) = 4; C(11,1) = 11](https://tex.z-dn.net/?f=C%284%2C3%29%20%3D%204%3B%20C%2811%2C1%29%20%3D%2011)
![P = \frac{C(4,3)*C(11,1)}{C(15,4)} = \frac{4*11}{1365} = 0.03223](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7BC%284%2C3%29%2AC%2811%2C1%29%7D%7BC%2815%2C4%29%7D%20%3D%20%5Cfrac%7B4%2A11%7D%7B1365%7D%20%3D%200.03223)
c) ![C(4,2) = 6; C(11,2) = 55](https://tex.z-dn.net/?f=C%284%2C2%29%20%3D%206%3B%20C%2811%2C2%29%20%3D%2055)
![P = \frac{C(4,2)*C(11,2)}{C(15,4)} = \frac{6*55}{1365} = 0.2418](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7BC%284%2C2%29%2AC%2811%2C2%29%7D%7BC%2815%2C4%29%7D%20%3D%20%5Cfrac%7B6%2A55%7D%7B1365%7D%20%3D%200.2418)
d) ![C(11,4) = 330](https://tex.z-dn.net/?f=C%2811%2C4%29%20%3D%20330)
![P = \frac{C(11,4)}{C(15,4)} = \frac{330}{1365} = 0.2418](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7BC%2811%2C4%29%7D%7BC%2815%2C4%29%7D%20%3D%20%5Cfrac%7B330%7D%7B1365%7D%20%3D%200.2418)
Answer:
sum of all forces on the air plane must be ZERO
So both forces must be of same magnitude
Explanation:
As we know that airplane is moving with uniform speed is horizontal plane is a straight line
so the motion of the air plane is uniform without any acceleration
So we will have
![a = 0](https://tex.z-dn.net/?f=a%20%3D%200)
acceleration must be zero
now by Newton's law
![F_{net} = 0](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%200)
![F_1 + F_2 = 0](https://tex.z-dn.net/?f=F_1%20%2B%20F_2%20%3D%200)
so sum of all forces on the air plane must be ZERO