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Anastasy [175]
3 years ago
9

When I wave a charged golf tube at the front of the classroom with a frequency of two oscillations per second, I produce an elec

tromagnetic wave of frequency 2Hz. What is the wavelength of this wave? (a) 6.7 × 10−9m (b) 1.5 × 108m (c) 3.0 × 108m (d) 6.0 × 108m
Physics
1 answer:
solmaris [256]3 years ago
3 0

To solve this problem it is necessary to apply the concepts related to Wavelength depending on the frequency and speed of light.

The equation that meets these parameters is given by

\lambda = \frac{c}{f}

Where,

c = Speed of light

\lambda = Wavelength

f = Frequency

Our values are given as

c = 3*10^8m/s \rightarrow velocity of light in free space

f = 2Hz

Replacing we have that

\lambda = \frac{c}{f}\\\lambda = \frac{3*10^8}{2}\\\lambda = 1.5*10^8m

Therefore the correct answer is B.

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The intensity at distance from a spherically symmetric sound source is 100 W/m2. What is the intensity at five times this distan
ss7ja [257]

To solve this problem it is necessary to apply the concepts related to intensity as a function of power and area.

Intensity is defined to be the power per unit area carried by a wave. Power is the rate at which energy is transferred by the wave. In equation form, intensity I is

I = \frac{P}{A}

The area of a sphere is given by

A = 4\pi r^2

So replacing we have to

I = \frac{P}{4\pi r^2}

Since the question tells us to find the proportion when

r_1 = 5r_2 \rightarrow \frac{r_2}{r_1} = \frac{1}{5}

So considering the two intensities we have to

I_1 = \frac{P_1}{4\pi r_1^2}

I_2 = \frac{P_2}{4\pi r_2^2}

The ratio between the two intensities would be

\frac{I_1}{I_2} = \frac{ \frac{P_1}{4\pi r_1^2}}{\frac{P_2}{4\pi r_2^2}}

The power does not change therefore it remains constant, which allows summarizing the expression to

\frac{I_1}{I_2}=(\frac{r_2}{r_1})^2

Re-arrange to find I_2

I_2 = I_1 (\frac{r_1}{r_2})^2

I_2 = 100*(\frac{1}{5})^2

I_2 = 4W/m^2

Therefore the intensity at five times this distance from the source is 4W/m^2

3 0
3 years ago
A concave mirror always forms a virtual image of a real object. O True O False
kifflom [539]

Answer:

The given statement is false.

Explanation:

The spherical mirrors are the mirror that are a part of a sphere. Concave and convex mirrors are two types of spherical mirrors.

A concave mirror always forms real and inverted image. A convex mirror forms real and virtual images.

For concave mirror, the value of magnification is less that 1. Also, the focal length is negative for concave mirrors.

So, the given statement is false as a concave mirror always forms a real and inverted image. Hence, this is the required solution.

4 0
3 years ago
The ratio of output power to input power, in percent, is called
kow [346]

That ratio is called"efficiency".  It doesn't need to be a percent. 
It can just as well be a fraction or a decimal number.

3 0
3 years ago
Does kinetic energy stay the same at all heights? pls help I have 12 minutes to finish the project and the teacher won't help me
Alex Ar [27]

Answer:

Kinetic energy does not stay the same at all heights

Explanation:

Well as the height and wind increase so does the kinetic energy it's like when you fall as you are about to hit the floor you speed increases

HOPE THIS HELPS YA :)

7 0
3 years ago
Sarah walks WEST a distance of 5 meters then turns NORTH and walks 8
Leokris [45]

Answer:

she is 3 meters in north

Explanation:

3 0
3 years ago
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