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Anastasy [175]
3 years ago
9

When I wave a charged golf tube at the front of the classroom with a frequency of two oscillations per second, I produce an elec

tromagnetic wave of frequency 2Hz. What is the wavelength of this wave? (a) 6.7 × 10−9m (b) 1.5 × 108m (c) 3.0 × 108m (d) 6.0 × 108m
Physics
1 answer:
solmaris [256]3 years ago
3 0

To solve this problem it is necessary to apply the concepts related to Wavelength depending on the frequency and speed of light.

The equation that meets these parameters is given by

\lambda = \frac{c}{f}

Where,

c = Speed of light

\lambda = Wavelength

f = Frequency

Our values are given as

c = 3*10^8m/s \rightarrow velocity of light in free space

f = 2Hz

Replacing we have that

\lambda = \frac{c}{f}\\\lambda = \frac{3*10^8}{2}\\\lambda = 1.5*10^8m

Therefore the correct answer is B.

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Instead of moving back and forth, a conical pendulum moves in a circle at constant speed as its string traces out a cone (see fi
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Answer:

a

The  radial acceleration is  a_c  = 0.9574 m/s^2

b

The horizontal Tension is  T_x  = 0.3294 i  \ N

The vertical Tension is  T_y  =3.3712 j   \ N

Explanation:

The diagram illustrating this is shown on the first uploaded

From the question we are told that

   The length of the string is  L =  10.7 \ cm  =  0.107 \ m

     The mass of the bob is  m = 0.344 \  kg

     The angle made  by the string is  \theta  =  5.58^o

The centripetal force acting on the bob is mathematically represented as

         F  =  \frac{mv^2}{r}

Now From the diagram we see that this force is equivalent to

     F  =  Tsin \theta where T is the tension on the rope  and v is the linear velocity  

     So

          Tsin \theta  =   \frac{mv^2}{r}

Now the downward normal force acting on the bob is  mathematically represented as

          Tcos \theta = mg

So

       \frac{Tsin \ttheta }{Tcos \theta }  =  \frac{\frac{mv^2}{r} }{mg}

=>    tan \theta  =  \frac{v^2}{rg}

=>   g tan \theta  = \frac{v^2}{r}

The centripetal acceleration which the same as the radial acceleration  of the bob is mathematically represented as

      a_c  =  \frac{v^2}{r}

=>  a_c  = gtan \theta

substituting values

     a_c  =  9.8  *  tan (5.58)

     a_c  = 0.9574 m/s^2

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substituting value

   T_x  = 0.344 *  0.9574

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    T_y  =  T \ cos \theta  = mg

substituting value

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       T  = T_x i  + T_y  j

substituting value  

      T  = [(0.3294) i  + (3.3712)j ] \  N

         

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