Additional information to complete the question:
How long does it take for a short pulse of light to travel from one end of the glass to the other?
Express your answer in terms of some or all of the variables f and L. Use the numeric value given for n in the introduction.
T = ___________ s
Answer:
Step-by-step explanation:
Given:
Thickness og glass = L
Index of refraction n=1.5
Frequency = f
λ(air) 
λ(glass) = λ(air) / n
= 
= 
= 
V(glass) = fλ(glass)
The answer is D because
60 times 5=300
20 times 8=160
25 times 9=225
33 times 10=330
Then add all of them and it gives you $1,015
Answer:
1. 8.85 quarts
2. 44.25%
Step-by-step explanation:
In 15 quarts of a solution with percentage of antifreeze = 35%
Amount of antifreeze = 35% × 15
= 0.35 × 15
= 5.25 quarts
that solution is mixed with 5 quarts of a solution with percentage of antifreeze = 72%
Amount of antifreeze = 72% × 5
= 0.72 × 5
= 3.6 quarts
Total amount of mixture = 15 quarts + 5 quarts = 20 quarts
1. Now we will calculate the total amount of antifreeze in the resulting mixture.
= 5.25 + 3.6 = 8.85 quarts
2. The percentage of the resulting mixture is antifreeze
= 
= 44.25%
1. total amount of antifreeze is 8.85 quarts
2. the percentage of antifreeze is 44.25%
Answer: ![3x^2y\sqrt[3]{y}\\\\](https://tex.z-dn.net/?f=3x%5E2y%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C)
Work Shown:
![\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27x%5E%7B6%7Dy%5E%7B4%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B3%2B3%7Dy%5E%7B3%2B1%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B3%7D%2Ax%5E%7B3%7D%2Ay%5E%7B3%7D%2Ay%5E%7B1%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B2%2A3%7D%2Ay%5E%7B3%7D%2Ay%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cleft%283x%5E2y%5Cright%29%5E3%2Ay%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cleft%283x%5E2y%5Cright%29%5E3%7D%2A%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C3x%5E2y%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C)
Explanation:
As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.
