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Strike441 [17]
4 years ago
14

Which of the following fractions can be used in the conversion of 25 m3 to the unit cm3?

Chemistry
1 answer:
zaharov [31]4 years ago
8 0

your answer would be C hope this helps

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Explanation:

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According to the following reaction, how many grams of water are produced in the complete reaction of 29.7 grams of ammonia? 4 N
Gnesinka [82]

<u>Answer:</u> The mass of water produced in the reaction is 47.25 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of ammonia = 29.7 g

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

\text{Moles of ammonia}=\frac{29.7g}{17g/mol}=1.75mol

The given chemical reaction follows:

4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)

By stoichiometry of the reaction:

4 moles of ammonia produces 6 moles of water.

So, 1.75 moles of ammonia will produce = \frac{6}{4}\times 1.75=2.625mol of water.

Now, calculating the mass of water by using equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 2.625 moles

Putting values in equation 1, we get:

2.625mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=47.25g

Hence, the mass of water produced in the reaction is 47.25 grams.

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3 years ago
How many atoms does NH4Br have
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6

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bromine has 1, hydrogen has 4 and nitrogen has 1 therefore equaling 6

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Unburned hydrocarbon on reacting with oxygen undergoes combustion reaction. However, the activation energy of this reaction is significantly high. When a catalyst like Pd is added to the reaction system, it provides active sites for the reaction to occur. It acts are a heterogeneous catalyst. It is pertinent of note that catalyst is refereed as heterogeneous, when it exist in different phase as compared to reactant and products. In present case, reactants and products are in gas phase, while catalyst is in solid phase. Due to availability of larger surface area at active site of Pd, activation energy of reaction decreases and decrease in activation energy favors higher reaction rates. 
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