1.661x10 negative 24 squared
3. B
4. A
5.A
6. A (i think)
Hope this helps
<h3>
Answer:</h3>
0.90J/g°C
<h3>
Explanation:</h3>
We are given:
Mass of Aluminium = 10 g
Quantity of heat = 677 Joules
Change in temperature = 125°C - 50°C
= 75°C
We are required to calculate the specific heat capacity of Aluminium
But, Quantity of heat = Mass × specific heat × Change in temperature
Q = mcΔt
Rearranging the formula;
c = Q ÷ mΔt
= 677 J ÷ (10 g × 75°C)
= 677 J ÷ 750g°C
= 0.903 J/g°C
= 0.90J/g°C
Thus, the specific heat capacity of Aluminium is 0.90J/g°C
Answer:
The Answer is D: A solid with no repeating pattern in its structure
Explanation:
