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lyudmila [28]
3 years ago
14

Over a long period of time, an igneous rock changes into a sedimentary rock. Which of these actions must have affected the igneo

us rock in order to form the sedimentary rock? The minerals must have been dissolved in water. It must have melted and become magma. It must have been broken down into sediments. The pressure and temperature must have been high.
Chemistry
1 answer:
Alla [95]3 years ago
3 0

Answer: The actions that must have affected the igneous rock in order to form the sedimentary rock is that (It must have been broken down into sediments).

Explanation:

Rocks are solid structures that occurs naturally which is made up of different minerals. There are three main types of rocks, these includes:

--> METAMORPHIC ROCKS: These are the type of rocks which are formed by temperature and pressure changes inside the Earth.

--> SEDIMENTARY ROCKS: these rocks are usually formed from pre-existing rocks through the process of weathering (breaking down) of rocks.

--> IGNEOUS ROCKS: these rocks are formed when molten magma cools beneath or above the earth surface.

The actions that must have affected the igneous rock in order to form the sedimentary rock is that the igneous rocks are broken down into smaller pieces by erosion and weathering processes. Sediments which are formed accumulates at the earth surface. Over a long period of time, these sediments builds successive layers on top of one another. The sediments near the base hardens to form sedimentary rocks. This justifies the statement as a correct option (It must have been broken down into sediments).

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What is the new concentration of 25.0mL added to 125.0mL of 0.150M
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Answer:

The new concentration is 0.125 M.

Explanation:

Given data:

Initial volume V₁ = 125.0 mL

Initial molarity M₁ = 0.150 M

New volume V₂ = 25 mL +125 mL = 150 mL

New concentration M₂ = ?

Solution:

M₁V₁    =    M₂V₂

0.150 M × 125 mL = M₂ × 150 mL

M₂ = 0.150 M × 125 mL / 150mL

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M₂ = 0.125 M

The new concentration is 0.125 M.

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5 0
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A chemist wants to make 6.5 L of a .350M CaCl2 solution. What mass of CaCl2(in g) should the chemist use?
kotykmax [81]
First M stands for Molarity which is (moles of solute) / (Liters of solution). we also know that moles = (mass) / (molar mass). so we can form some equations here. We know:
Molarity (M) = moles (mol) / Liters (L)
moles (mol) = (mass) / (molar mass)

we can substitute the (mass) / (molar mass) for (moles) and get:
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we can now isolate mass and get
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now we need to find the molar mass of CaCl2 which is 110.98 g/mol

plug the values in and get
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mass = 252.4795g however the 6.5L has only 2 sig figs so i would say

mass CaCl2 = 2.5 * 10 ^2 g
5 0
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Answer:

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