7.) Area of a square pyramid is given by A = s^2 + 2sl; where s is the side length of the base and l is the slant height.
Area of given pyramid = 4^2 + (2 x 4 x 7) = 16 + 56 = 72 ft^2
8.) Area of the given pyramid is the area of the hexagonal base plus the area of the six slant triangles.
Area of hexagonal base = (3sqrt(3))/2 x 10^2 = 150 x 1.732 = 259.8
Area of the 6 traingles = 6(1/2 x 10 x 13) = 6 x 65 = 390
Total surface area of the pyramid = 259.8 + 390 = 649.8 ≈ 650 m^2
9.) Using pythagoras rule, the slant height is sqrt(6^2 + 3.5^2) = sqrt(36 + 12.25) = sqrt(48.25) = 6.9 mm
10.) The surface area of a cone is given by πr^2 + πrl
Area = π x 6^2 + π x 6 x 20 = 36π + 120π = 490.1 cm^2
11.) l = sqrt(r^2 + h^2) = sqrt(11^2 + 16^2) = sqrt(121 + 256) = sqrt(377) = 19m
Answer:
y=-1/4x-5 1/2.
Step-by-step explanation:
Using the formula y-y1=m(x-x1), plug in the slope and the numbers and you'll get y=-1/4x-5 1/2.
Answer:
C
Step-by-step explanation:
transposition
3x/4=1/5
xc=yc
15x/20×20=4/20×20
15x=4
x=4/15
7 because 7x3= 21 and 21 + the 7 cats comes to an equal 28
3 decimal places would be where the 9 is, since the next number is 8 , the 9 would become a 0 and the number before it (5) would become a 6
so it would be 977.260
