Can someone help me with this question please

Alenkasestr [34]

I can't exactly SHOW you where to put the numbers, but I can teach you the process of how you'd do it.

First off, label your number line from 0-15, as it is the simplest. (You'd be counting by 1 per each line). Then, follow this process:

1) Look at the first digit of your value. Place your number according to your first digit. (So, you'd put 0.365 at the 0 line and 3.521 at the 3 line)

2) Look at the second digit of your value. Imagine that between the two main lines (0-1 and 3-4) that there is 10 smaller lines. Then, you can place your number according to your second digit. (So, you'd put 0.365 at the 0.3 line and 3.521 at the 3.5 line).

3) Look at the third digit of your value. Imagine that between the two smaller lines (0.3-0.4 and 3.5-3.6) that there is 10 smaller lines. Then, you can place your number according to your third digit. (So, you'd put 0.365 at the 0.36 line and 3.521 at the 3.52 line).

4) Look at the fourth digit of your value. Imagine that between the two even smaller lines (0.36-0.37 and 3.52-3.53) that there is 10 smaller lines. Then, you can place your number according to your fourth digit. (So you'd place 0.365 at the 0.365 line and 3.521 at the 3.521 line)

6 0

3 years ago

1. Solve the system by using a table. 3y=4x+7 , -4x-4y=28. These are the possible solutions: A) (–4, –3), B) (–3, –4), C) (4, 3)

melisa1 [442]

The first question:
3y=4x+7 (1)
-4x-4y=28 (2)

Let's plug in x = -4, -3, 3, and 4 and see the y-values :)

I have attached the table since it's hard to make a table with text :P
As you can see, when x = -4, that is when the y-values are equal. That means that is the solution to the system of equations. Your answer is A) (-4, -3).

The second question:
-3x-y=-10 (1)
4x-4y=8 (2)

When you graph both equations, you will see that they intersect at D) (3, 1).

The third question:
We need to find the lines for revenues and expenses.
To find the line for revenues, make months the x-value and revenues the y-values. And find the equation. You should get y = 4,100x + 300.
To find the line for expenses, make months the x-value and expenses the y-values. And find the equation. You should get y = 1,900x + 19,990.

Now graph both solutions and see where they intersect. They intersect at approximately (8.95, 36995)

That would be during the month of C) August.

4 0

3 years ago

Read 2 more answers

17. Farimah and Helio are standing 15 ft. apart from each other and looking up at a kite that is with the flying between them. F

miss Akunina [59]

Answer:

Helio is 53.2 feet from the kite ⇒ the last answer

Step-by-step explanation:

* Lets change this story problem to a trigonometry problem

- Assume that there is a triangle joining between the

kite, Farimah and Helio

- The name of the triangle is KFH, where K position of the kite,

F position of Farimah and H is the position of Helio

∵ Farimah and Helio are standing 15 feet apart from each other

∴ FH = 15 feet

∵ Farimah is flying the kite on a 57 feet string at an angle

of 68 with the ground

∴ FK = 57 feet

∴ m∠KFH = 68°

∵ We need to know that Helio is how far from the kite

∴ We need to calculate the length of KH

* Now lets find the best way to find the length of KH

using the trigonometry

- We have the length of two sides and the measure of the included

angle between them , then the best way is the cosine Rule

* Lets explain the cosine rule:

- In ΔABC:

∵ a is the length of the side opposite to ∠A ⇒ a is BC

∵ b is the length of the side opposite to ∠B ⇒ b is AC

∵ c is the length of the side opposite to ∠C ⇒ c = AB

∴ a² = b² + c² -2bc × cos(A)

∴ b² = a² + c² -2ac × cos(B)

∴ c² = a² + b² -2ab × cos(C)

* We will use the rule in our problem to find HK

∵ FH is k , HK is f , KF is h

∴ f² = h² + k² - 2hk × cos(F)

∵ h = 57 feet , k = 15 feet , m∠F = 68°

∴ f² = (57)² + (15)² - 2(57)(15) × cos(68) = 2833.4227

∴ f = √2833.4227 = 53.2 feet

* Helio is 53.2 feet from the kite

7 0

3 years ago

Find the product (4x-5y)^2

sleet_krkn [62]

To find the product of (4x-5y)^2,
we can rewrite the problem as:
(4x-5y)(4x-5y) (two times because it is squared)

Now, time to use that old method we learned in middle school:
FOIL. (Firsts, Outers, Inners, and Lasts)

FOIL can help us greatly in this scenario.
Let's start by multiplying the 'Firsts' together:
4x * 4x = 16x^2

Now, lets to the 'Outers':
4x * -5y = -20xy

Next, we can multiply the 'Inners':
-5y * 4x = -20xy

Finally, let's do the 'Lasts':
-5y * -5y = 25y^2

Now, we can take the products of these equations from FOIL and combine like terms. We have: 16x^2, -20xy, -20xy, and 25y^2.
-20xy and -20xy make -40xy.

The final equation (product of (4x-5y)^2) is:
16x^2 - 40xy + 25y^2

Hope I helped! If any of my math is wrong, please report and let me know!
Have a good one.

4 0

3 years ago

Please solve the problem below.

Liono4ka [1.6K]

Answer:

?=14

Step-by-step explanation:

12+5=17

8+8=16

8+4х8=40

4+6х4=28

9-5=4

9-12+5+8+4=14

5 0

3 years ago