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tankabanditka [31]
3 years ago
9

Show how to rewrite 1/5 with the denominator 10.

Mathematics
1 answer:
Gnoma [55]3 years ago
8 0

Answer:

first blank: 2

second blank: 2

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You can peel 48 potatoes in 10 minutes. How long will it take you to peel 100 potatoes?
dybincka [34]

Answer:

About 20.8 minutes

Step-by-step explanation:

TO solve this just think of it as a ratio. The number of potatoes goes on top and the time goes on bottom.

48

__

10

That is what the first one would look like. In the second one we know the number of potatoes but we are trying to find the time (x).

100

___

 x

Take these two ratios and set them equal to each other.

\frac{48}{10} =\frac{100}{x}      Next you cross multiply (take 48 times x and 100 times 10).

48x=1000    Now divide by 48 and you have your answer.

About 20.8 minutes

7 0
3 years ago
Test the divisibility of the following :<br>57624 is divisible by 6 ? If It is then explain.  <br>​
Alisiya [41]

Answer:

yes

Step-by-step explanation:

57624  \div 6 = 9607

7 0
2 years ago
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Pizza population sold 93 pizza on monday 67 pizza on Tuesday 78 pizza on wed 44 pizza on thur and 123 pizza on fri on average ho
swat32
81.
Add them all and then divide by the number of days (by 5)
3 0
3 years ago
What is 1/3 of 307? my question has to be at least 2 characters long soooo...
emmasim [6.3K]
1/3of 307 is 102.33
7 0
3 years ago
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Express 2x+1/(x-2)(x²+1) as a partial fraction.
Oduvanchick [21]

Answer:

Partial fraction = 1/(x-2) - x/(x^2+1)

Step-by-step explanation:

Question:

Express 2x+1/(x-2)(x²+1) as a partial fraction.

Note: it will be assumed that there was a typo in the interpretation of parentheses to mean

(2x+1) / ( (x-2)(x^2+1) )

Let

(2x+1) / ( (x-2)(x^2+1) ) = A/(x-2) + (Bx+C)/(x^2+1) .........................(0)

(2x+1) / ( (x-2)(x^2+1) ) = (A(x^2+1)+(Bx+C)(x-2)) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = (Ax^2+A+Bx^2+(C-2B)x-2C) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = ( (A+B)x^2+(C-2B)x+A-2C ) / ( (x-2)(B/(x^2+1) )

Match numerators

2x+1 = (A+B)x^2+(C-2B)x+A-2C

Match coefficients,

A+B = 0 ..................(1)

-2B+C = 2 .................(2)

A-2C = 1 ...................(3)

Solve for A, B and C

Substitute A from (1) in (3)

-B - 2C =1  

transpose and solve for B

B = -2C-1  ....................(4)

Substitue B from (4) in (2)

-2(-2C-1) + C = 2  

simplify

5C = 2-2 = 0

C=0  ..........................(5)

substitute (5)  in (4)

B = -2C-1 = -1  ...............(6)

Substitue (6) in (1)

A+(-1) = 0

A=1 .............................(7)

Using values from (7), (6) and (5) to substitute in (0)

we get

(2x+1) / ( (x-2)(x^2+1) ) = 1/(x-2) - x/(x^2+1)

as the required partial fraction

7 0
3 years ago
Read 2 more answers
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