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Digiron [165]
3 years ago
9

Why is accidental overlap of signals much more common in H-1 NMR than in C-13 NMR?

Chemistry
1 answer:
alexdok [17]3 years ago
5 0

Answer:

See explanation

Explanation:

Accidental overlap of signals are common in H-1 NMR than in C-13 NMR for the following reasons;

1) 13C has a very low  natural abundance compared to H-1

2) 13C nucleus is s many times lesser in NMR sensitivity than H-1 nucleus.

3) As a result of its low abundance,  13C-13C coupling is not common.

4) Longer relaxation times do not give room for integrations.

5) Peaks in 13C spectra mainly consists of single lines.

As a result of all these, 13C-NMR spectra take longer to acquire than H-NMR. Hence, accidental overlap of signals is much more common in H-1 NMR than in C-13 NMR.

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The molar mass of h2o is 18.01 g/mom . The molar mass of o2 is 32.00 g/moo .what mass of h2o on grams must react to produce 50.0
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Ethanol (CH3CH2OH), the intoxicant in alcoholic beverages, is also used to make other organic compounds. In concentrated sulfuri
Fed [463]

Answer:

a) 88.48%

b) 0.05625 mol

Explanation:

2CH₃CH₂OH(l) → CH₃CH₂OCH₂CH₃(l) + H₂O(g)         Reaction 1

CH₃CH₂OH(l) → CH₂═CH₂(g) + H₂O(g)                        Reaction 2

a) CH₃CH₂OH = 46.0684 g/mol

   CH₃CH₂OCH₂CH₃ = 74.12 g/mol

1 mol CH₃CH₂OH ______  46.0684 g

x                            ______   50.0 g

x = 1.085 mol  CH₃CH₂OH

1 mol  CH₃CH₂OCH₂CH₃ ______  74.12 g g

y                           ______   35.9 g

y = 0.48 mol   CH₃CH₂OCH₂CH₃

100% yield _____ 0.5425 mol CH₃CH₂OCH₂CH₃

w                _____  0.48 mol CH₃CH₂OCH₂CH₃

w = 88.48%

b) Only 0.96 mol of ethanol reacted to form diethyl ether. This means that 0.125 mol of ethanol did not react. 45% of 0.125 mol reacted to form ethylene. Therefore, 0.05625 mol of ethanol reacted by the side reaction (reaction 2). Since 1 mol of ethanol leads to 1 mol of ethylene, 0.05625 mol of ethanol produces 0.05625 mol of ethylene.

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3 years ago
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