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Aneli [31]
3 years ago
7

Find the R when p=6000,T=3 yrs 6 month ,I=1155​

Chemistry
1 answer:
MA_775_DIABLO [31]3 years ago
3 0

<h3><em>Answer:770</em></h3><h3 /><h3><em>R=I×100/P×T</em></h3>

<em>R</em><em>=</em><em> </em><em>1</em><em>1</em><em>5</em><em>5</em><em>×</em><em>1</em><em>0</em><em>0</em><em>/</em><em>6</em><em>0</em><em>0</em><em>0</em><em>×</em><em>3</em><em>/</em><em>1</em><em>2</em>

<em>R</em><em>=</em><em> </em><em>1</em><em>1</em><em>5</em><em>5</em><em>×</em><em>2</em><em>/</em><em>3</em>

<h3><em>R=770</em></h3>
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2 years ago
Analysis of skunk spray yields a molecule with 44.77% c, 7.46% h and 47.76% s by mass. what is the empirical formula for this mo
stiv31 [10]
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4 0
3 years ago
6. Describe the energy inputs and outputs for the campfire. Use the law of conservation of energy to construct a valid qualitati
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8 0
3 years ago
12. What is the frequency of a photon with an energy of 3.03 x 10-19 J?
bazaltina [42]

Answer:

u=4.57x10^5GHz

Explanation:

Hello.

In this case, given the formula:

E=h*u

Whereas E is the energy, h the Planck's constant and u the frequency of the photon. Thus, solving for it, we obtain:

u=\frac{E}{h}=\frac{3.03x10^{-19}J}{6.63x10^{-34}J*s}\\  \\u=4.57x10^{14}s^{-1}

Or also:

u=4.57x10^{14}Hz*\frac{1GHz}{1x10^9Hz}\\ \\u=4.57x10^5GHz

Best regards.

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3 years ago
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