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Natasha2012 [34]
3 years ago
5

Kyla, a business analyst uses test scripts while testing an application before it is released to the client. Why do business ana

lysts use test scripts?
A.
to perform acceptance testing
B.
to code functions correctly
C.
to write a test plan
D.
to create a test environment
E.
to review and update test cases
Computers and Technology
1 answer:
Mariana [72]3 years ago
8 0

Answer:

D. to create a test environment

Explanation:

After releasing it will be "production"

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Bond [772]

Answer:

The dark stories behind it? i dont  know lol

5 0
3 years ago
Ramesh goes to market for buying some fruits and vegetables .He
3241004551 [841]

Answer:

The algorithm is as follows

1. Start

2. Input Apple unit price

3. Input Mango unit price

4. input Tomato unit price

5. Total = Apple Price * 2 + Mango Price * 2 + Tomato Price

6. Display Total

7. End

Explanation:

Start the algorithm

1. Start

The next three lines gets input for the price of each fruit

<em>2. Input Apple unit price</em>

<em>3. Input Mango unit price</em>

<em>4. input Tomato unit price</em>

This calculates the total price

5. Total = Apple Price * 2 + Mango Price * 2 + Tomato Price

This displays the total price

6. Display Total

Stop the algorithm

7. End

5 0
3 years ago
I have a real struggle when it comes to working with strings, whether they're arrays or pointers to strings, and I'm lost cause
neonofarm [45]
In C, you deal with a string always via a pointer. The pointer by itself will not allocate memory for you, so you'll have to take care of that.

When you write char* s = "Hello world"; s will point to a "Hello world" buffer compiled into your code, called a string literal.

If you want to make a copy of that string, you'll have to provide a buffer, either through a char array or a malloc'ed bit of memory:

char myCopy[100];
strcpy(myCopy, s);

or 

char *myCopy;
myCopy = (char*)malloc( strlen(s) + 1 );
strcpy(myCopy, s);

The malloc'ed memory will have to be returned to the runtime at some point, otherwise you have a memory leak. The char array will live on the stack, and will be automatically discarded.

Not sure what else to write here to help you...
6 0
3 years ago
How can my computer catch a virus?
Lapatulllka [165]
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4 0
3 years ago
Convert the following Base 10 (decimal) numbers to base 2(binary):<br> 107<br> 200
melamori03 [73]

<u>Answer:</u>

107₁₀ - 1101011

₂ (Binary representation)

200₁₀- 11001000₂ (Binary representation)

<u>Explanation:</u>

Converting from Decimal to binary:

Procedure -

1. Divide the number by 2, write the reminder separately.

2. Divide the divisor by 2, write the reminder before the previously written reminders.

Keep doing this till you get your divisor as 1.

Then we will write the divisor  before the written reminders and that will be the binary representation.

   

 For 107 :

       

          We divide 107 by 2 ,we get the divisor 53 and remainder 1

                                                  ( 1 )

Then,we will divide this divisor i.e 53 by 2,we get divisor 26 and remainder 1 ,we will put this remainder before the previous one.

                                                ( 1 1 )      

Then,we will divide this divisor i.e 26 by 2,we get divisor 13 and remainder 0 ,we will put this remainder before the previous one.    

                                                 ( 0 1 1 )

Then,we will divide this divisor i.e 13 by 2,we get divisor 6 and remainder 1 ,we will put this remainder before the previous one.    

                                                 ( 1 0 1 1 )

Then,we will divide this divisor i.e 6 by 2,we get divisor 3 and remainder 0,we will put this remainder before the previous one.    

                                                 ( 0 1 0 1 1 )

Then,we will divide this divisor i.e 3 by 2,we get divisor 1 and remainder 1  ,we will put this remainder before the previous one.    

                                                 ( 1 0 1 0 1 1 )

As we get the divisor=1,then we will stop.we will write the divisor before the written reminders.

                                              ( 1 1 0 1 0 1 1 )

This will be the binary representation of 107.

For 200 :

         We divide 200 by 2 ,we get the divisor 100 and remainder 0

                                                  ( 0 )

Then,we will divide this divisor i.e 100 by 2,we get divisor 50 and remainder 0 ,we will put this remainder before the previous one.

                                                ( 0 0 )      

Then,we will divide this divisor i.e 50 by 2,we get divisor 25 and remainder 0 ,we will put this remainder before the previous one.    

                                                 ( 0 0 0 )

Then,we will divide this divisor i.e 25 by 2,we get divisor 12 and remainder 1 ,we will put this remainder before the previous one.    

                                                 ( 1 0 0 0 )

Then,we will divide this divisor i.e 12 by 2,we get divisor 6 and remainder 0 ,we will put this remainder before the previous one.    

                                                 ( 0 1 0 0 0 )

Then,we will divide this divisor i.e 6 by 2,we get divisor 3 and remainder 0  ,we will put this remainder before the previous one.    

                                                 ( 0 0 1 0 0 0 )

Then,we will divide this divisor i.e 3 by 2,we get divisor 1 and remainder 1,we will put this remainder before the previous one.    

                                                 ( 1 0 0 1 0 0 0 )

As we get the divisor=1,then we will stop.we will write the divisor before the written reminders.

                                                 ( 1 1 0 0 1 0 0 0 )

This will be the binary representation of 200.

7 0
3 years ago
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