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3 years ago

A 2.0kg object is raised by a height of 0.5m.Calculate the energy raised in its gravitational potential energy store? G=9.8N/KG

Physics

1 answer:

notka56 [123]3 years ago

5 0

Answer:

Gravitational potential energy stored is 9.8 J.

Given:

G = 9.8 $\frac{N}{kg}$

height = 0.5 m

mass = 2 kg

To find:

Gravitation Potential energy stored = ?

Formula used:

Potential energy = mGh

m = mass

G = acceleration due to gravity

h = height

Solution:

Potential energy of the object is given by,

Potential energy = mGh

m = mass

G = acceleration due to gravity

h = height

Potential energy = 2 × 9.8 × 0.5

Potential energy = 9.8 Joule

Gravitational potential energy stored is 9.8 J.

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Answer:

Part a)

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Part b)

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Part c)

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Explanation:

Part a)

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Part b)

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$v_x = 24.5 m/s$

now the distance moved by it

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Since the distance of other building is 15 m so YES it can make it to other building

Part c)

Final velocity in X direction will remains the same

$v_x = 24.5 m/s$

final velocity in Y direction

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$v_y = 0 + (7.36)(1.65)$

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now magnitude of velocity is given as

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$v = \sqrt{24.5^2 + 12.14^2}$

$v = 27.3 m/s$

direction of velocity is given as

$\theta = tan^{-1}\frac{v_y}{v_x}$

$\theta = tan^{-1}\frac{12.14}{24.5}$

$[tex]\theta = 26.35 degree$

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