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Bumek [7]
2 years ago
8

A 2.0kg object is raised by a height of 0.5m.Calculate the energy raised in its gravitational potential energy store? G=9.8N/KG

Physics
1 answer:
notka56 [123]2 years ago
5 0

Answer:

Gravitational potential energy stored is 9.8 J.

Given:

G = 9.8 \frac{N}{kg}

height = 0.5 m

mass = 2 kg

To find:

Gravitation Potential energy stored = ?

Formula used:

Potential energy = mGh

m = mass

G = acceleration due to gravity

h = height

Solution:

Potential energy of the object is given by,

Potential energy = mGh

m = mass

G = acceleration due to gravity

h = height

Potential energy = 2 × 9.8 × 0.5

Potential energy = 9.8 Joule

Gravitational potential energy stored is 9.8 J.

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nalin [4]

Explanation:

The volume of the bread decreases, making the bread appear more compact, and smaller in size. The mass stays the same, it won't change unless part of the bread is removed. The density increases, the air bubbles inside of the bread get squished down, causing the bread to be smaller, and in turn, causing it to be more solid.

I hope this helped!

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3 0
3 years ago
How much work does it take to lift 345 boxes to a height of 6.00 m of each box has a mass of 7.89 kg
Art [367]

Given the value of the mass of each boxes, the work done in lifting the boxes to the given height is 1.6 × 10⁵J.

<h3>Work done</h3>

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = F × d

Where F is force applied or Weight and d is distance

Also Force = Weight = mass × acceleration due to gravity.

Since gravity is acting on the boxes as it been lift

W = Weight × height from ground level

W = mg × d

Where m is mass of the boxes, g is accelration due to gravity( g = 9.8m/s² ) and d is distance from ground level.

Given the data in the question;

  • Since each box has a mass of 7.89 kg
  • Mass of the 345 boxes = 345 × 7.89 kg = 2722.05kg
  • Distance or height d = 6.0m
  • Work done W = ?

To determine the work done, we substitute our values into the expression above.

W = mg × d

W = 2722.05kg × 9.8m/s² × 6.0m

W = 160056.5kgm²/s²

W = 160056.5J

W = 1.6 × 10⁵J

Therefore,  Given the value of the mass of each boxes, the work done in lifting the boxes to the given height is 1.6 × 10⁵J.

Learn more about work done here: brainly.com/question/26115962

3 0
2 years ago
A bullet starting from rest accelerates uniformly at a rate of 1,250 meters per square second. What is the bullet's speed after
Tatiana [17]

Answer:

125,000

Explanation:

8 0
3 years ago
Which substance is a combination of different atoms?
Lady_Fox [76]

Answer:

The answer is compound

Explanation:

heterogeneous mixture is wronggggg

5 0
2 years ago
Convert <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%280.779mg%29%28min%29%7D%7BL%7D" id="TexFormula1" title="\frac{(0.779mg)(mi
Orlov [11]

The number converted is 0.0467 \frac{(kg)(s)}{m^3}

Explanation:

In order to convert from the original units to the final units, we have to keep in mind the following conversion factors:

1 kg = 1000 g = 10^6 mg

1 min = 60 s

1 m^3 = 1000 L

The original unit that we have is

\frac{mg\cdot min}{L}

Therefore, it can be rewritten as:

=\frac{mg \frac{1}{10^6 mg/kg}\cdot min\cdot  60 s/min}{L\frac{1}{1000L/m^3}}=0.06 \frac{(kg)(s)}{m^3}

Therefore, since the initial number was 0.779, the final value is

0.779\cdot 0.06 \frac{(kg)(s)}{m^3}=0.0467 \frac{(kg)(s)}{m^3}

#LearnwithBrainly

5 0
3 years ago
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