All categories

2 years ago

what current flows through a 2.54cm diameter rod of pure silicon that is 20.0cm long ,when 1.00x10000V is applied to it

Physics

1 answer:

Andrej [43]2 years ago

8 0

0.04 Ampere of current will flow through the silicon.

<h3>What is Electrical Current ?</h3>

Electrical current is the rate at which charges flow in the conductor. It is measured in Ampere (A)

What current flows through a 2.54cm diameter rod of pure silicon that is 20.0cm long ,when 1.00x10000V is applied to it

The given diameter is 2.54 cm, the radius r = 2.54/2 = 1.27 cm

Convert cm to m

r = 1.27/100 = 0.0127m

L = 20/100 = 0.2m

Area A = πr²

A = π × 0.0127²

A = 0.000507 m²

The resistivity ρ of silicon material is 640 Ωm

Resistance R = ρL / A

R = ( 640 × 0.2 ) / 0.000506

R = 128 / 0.000506

R = 252964.43 Ω

From Ohm's law

V = IR

10000 = 252964.43I

I = 10000 / 252964.43

I = 0.0395A

Therefore, 0.04 Ampere of current will flow through the silicon.

Learn more about Current here: brainly.com/question/24858512

#SPJ1

You might be interested in

PLEASE HELP TIMED

Igoryamba

Radio waves have longer wavelengths and lower frequencies than microwaves.

infrared is longer wavelengths and lower frequencies than UV light

5 0

3 years ago

Read 2 more answers

4. While broadcasting a football game, the announcer exclaimed, "I can't believe it. Carl James just scored a touchdown. That's

Zielflug [23.3K]

D. Carl doesnt score touchdowns very often.

7 0

4 years ago

Read 2 more answers

Heat is added to a 2kg piece of ice at a rate of 793kW. How long will it take for ice to melt if it was initially 0?

Ede4ka [16]

Answer:

0.84 s

Explanation:

Step 1

Given information:

Mass of the ice (m) = 2.0 kg

Heat transfer rate (Q/T) = 793.0 kW

Latent heat of fusion of ice (Lf) = 334 kJ/kg

$\frac{Q}{T} = \frac{mLf}{T}$

Substituting the corresponding values we have:

$793.0 kW= \frac{2.0kg(334 kJ/kg)}{T} \\ T = \frac{2.0kg(334 kJ/kg)}{793.0kW} = \frac{668kJ}{793kW} \\ = 0.84s$

8 0

3 years ago

A space shuttle with a mass of approximately 7.08 E5 kg is sitting on the launch pad. What would be the weight of the space shut

Afina-wow [57]

The weight of the shuttle is $6.94\cdot 10^6 N$

Explanation:

The weight of an object on Earth is the gravitational force exerted by the Earth on the object.

The magnitude of the weight of an object is given by:

$W=mg$

where

m is the mass of the object

$g=9.8 m/s^2$ is the acceleration of gravity on Earth's surface

And the direction is downward (towards the Earth's centre).

For the shuttle in this problem, its mass is

$m=7.08\cdot 10^5 kg$

So, its weight is

$W=(7.08\cdot 10^5)(9.8)=6.94\cdot 10^6 N$

Note that while the mass of an object (m) does not change, its weight (W) changes according to the location, since the value of g can be different at different location (for example, on the Moon, the value of g is about 1/6 the value of g on the Earth).

Learn more about weight and forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

6 0

3 years ago

Figure 3 shows a bicycle of mass 15 kg resting in a vertical position, with the front and back

Vinil7 [7]

Explanation:

There are three forces on the bicycle:

Reaction force Rp pushing up at P,

Reaction force Rq pushing up at Q,

Weight force mg pulling down at O.

There are four equations you can write: sum of the forces in the y direction, sum of the moments at P, sum of the moments at Q, and sum of the moments at O.

Sum of the forces in the y direction:

Rp + Rq − (15)(9.8) = 0

Rp + Rq − 147 = 0

Sum of the moments at P:

(15)(9.8)(0.30) − Rq(1) = 0

44.1 − Rq = 0

Sum of the moments at Q:

Rp(1) − (15)(9.8)(0.70) = 0

Rp − 102.9 = 0

Sum of the moments at O:

Rp(0.30) − Rq(0.70) = 0

0.3 Rp − 0.7 Rq = 0

Any combination of these equations will work.

3 0

3 years ago