All categories

1 year ago

what current flows through a 2.54cm diameter rod of pure silicon that is 20.0cm long ,when 1.00x10000V is applied to it

Physics

1 answer:

Andrej [43]1 year ago

8 0

0.04 Ampere of current will flow through the silicon.

<h3>What is Electrical Current ?</h3>

Electrical current is the rate at which charges flow in the conductor. It is measured in Ampere (A)

What current flows through a 2.54cm diameter rod of pure silicon that is 20.0cm long ,when 1.00x10000V is applied to it

The given diameter is 2.54 cm, the radius r = 2.54/2 = 1.27 cm

Convert cm to m

r = 1.27/100 = 0.0127m

L = 20/100 = 0.2m

Area A = πr²

A = π × 0.0127²

A = 0.000507 m²

The resistivity ρ of silicon material is 640 Ωm

Resistance R = ρL / A

R = ( 640 × 0.2 ) / 0.000506

R = 128 / 0.000506

R = 252964.43 Ω

From Ohm's law

V = IR

10000 = 252964.43I

I = 10000 / 252964.43

I = 0.0395A

Therefore, 0.04 Ampere of current will flow through the silicon.

Learn more about Current here: brainly.com/question/24858512

#SPJ1

You might be interested in

It decomposes in a first-order reaction with a rate constant of 14 s–1. how long would it take for an initial concentration of 0

VikaD [51]

The rate constant of a reaction can be computed by the ratio of the changes in the concentration and time take taken for it to decompose. Thus, if the rate constant is given to be 14 M/s, we have

$rate = \frac{-(C_{new} - C_{old})}{t}$

where C are the concentration values and t is the time taken for it to decompose.

$14 = \frac{-(0.02 - 0.06)}{t}$
$t = 0.003 s$

Thus, it will take 0.003 s for it to decompose.
Answer: 0.003 s

4 0

3 years ago

Where do seasons alternate between a very dry season and a monsoon season, with a stable warm climate?

Angelina_Jolie [31]

That would be a savanna climate

7 0

3 years ago

Plants are made of_________________cells, which have membrain-bound_____.

Readme [11.4K]

Plant cells are eukaryotic cells that differ in several key aspects from the cells of other eukaryotic organisms. number two sry but Idk
:(

4 0

3 years ago

Two workers are sliding 300 kg crate across the floor. One worker pushes forward on the crate with a force of 400 N while the ot

almond37 [142]

Answer:

The kinetic coefficient of friction of the crate is 0.235.

Explanation:

As a first step, we need to construct a free body diagram for the crate, which is included below as attachment. Let supposed that forces exerted on the crate by both workers are in the positive direction. According to the Newton's First Law, a body is unable to change its state of motion when it is at rest or moves uniformly (at constant velocity). In consequence, magnitud of friction force must be equal to the sum of the two external forces. The equations of equilibrium of the crate are:

$\Sigma F_{x} = P+T-\mu_{k}\cdot N = 0$ (Ec. 1)

$\Sigma F_{y} = N - W = 0$ (Ec. 2)

Where:

$P$ - Pushing force, measured in newtons.

$T$ - Tension, measured in newtons.

$\mu_{k}$ - Coefficient of kinetic friction, dimensionless.

$N$ - Normal force, measured in newtons.

$W$ - Weight of the crate, measured in newtons.

The system of equations is now reduced by algebraic means:

$P+T -\mu_{k}\cdot W = 0$

And we finally clear the coefficient of kinetic friction and apply the definition of weight:

$\mu_{k} =\frac{P+T}{m\cdot g}$

If we know that $P = 400\,N$ , $T = 290\,N$ , $m = 300\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , then:

$\mu_{k} = \frac{400\,N+290\,N}{(300\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}$

$\mu_{k} = 0.235$

The kinetic coefficient of friction of the crate is 0.235.

5 0

3 years ago

A person is standing on a scale in an unmoving elevator. The elevator starts to move upwards at 1 m/s squared. Is the scale read

timama [110]

Answer: GREATER

Explanation:when elevator does not move it reads weight of the person . when elevator moves up let apparent weight be F . W acts downwards so net force is F-W

HENCE

F-W =ma

F= ma+W

AS a= 1 m/s^2

F = m (1)+W

HENCE GREATER

7 0

3 years ago