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Ratling [72]
1 year ago
12

what current flows through a 2.54cm diameter rod of pure silicon that is 20.0cm long ,when 1.00x10000V is applied to it

Physics
1 answer:
Andrej [43]1 year ago
8 0

0.04 Ampere of current will flow through the silicon.

<h3>What is Electrical Current ?</h3>

Electrical current is the rate at which charges flow in the conductor. It is measured in Ampere (A)

What current flows through a 2.54cm diameter rod of pure silicon that is 20.0cm long ,when 1.00x10000V is applied to it

The given diameter is 2.54 cm, the radius r = 2.54/2 = 1.27 cm

Convert cm to m

  • r = 1.27/100 = 0.0127m
  • L = 20/100 = 0.2m

Area A = πr²

A = π × 0.0127²

A = 0.000507 m²

The resistivity ρ of silicon material is 640 Ωm

Resistance R =  ρL / A

R = ( 640 × 0.2 ) / 0.000506

R = 128 / 0.000506

R = 252964.43 Ω

From Ohm's law

V = IR

10000 = 252964.43I

I = 10000 / 252964.43

I = 0.0395A

Therefore, 0.04 Ampere of current will flow through the silicon.

Learn more about Current here: brainly.com/question/24858512

#SPJ1

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Does the depth of a pot affect how water freezes
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3 0
3 years ago
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You are removing branches from your roof after a big storm. You throw a branch horizontally from your roof, which is a height 3.
mart [117]

Answer:

The initial velocity in the x-direction with which the branch was thrown is approximately 10.224 m/s

Explanation:

The given parameters of the motion of the branch are;

The height from which the branch is thrown = 3.00 m

The horizontal distance the branch lands from where it was thrown, x = 8.00 m

The direction in which the branch is thrown = Horizontally

Therefore, the initial vertical velocity of the branch, u_y = 0 m/s

The time it takes an object in free fall (zero initial downward vertical velocity) to reach the ground is given as follows;

s = u_y·t + 1/2·g·t²

Where;

u_y = 0 m/s

s = The initial height of the object = 3.00 m

g = The acceleration due to gravity = 9.8 m/s²

∴ s = 0·t + 1/2·g·t² = 0 × t + 1/2·g·t² = 1/2·g·t²

t = √(2·s/g) = √(2 × 3/9.8) = (√30)/7 ≈ 0.78246

The horizontal distance covered before the branch touches the ground, x = 8.00 m

Therefore, the initial velocity in the horizontal, x-direction with which the branch was thrown, 'uₓ', is given as follows;

uₓ = x/t = 8.00 m/((√30)/7 s)

Using a graphing calculator, we get;

uₓ = 8.00 m/((√30)/7 s) = (28/15)·√30 m/s ≈ 10.224 m/s

The initial velocity in the horizontal, x-direction with which the branch was thrown, uₓ ≈ 10.224 m/s.

3 0
3 years ago
Which statement is true according to Newton's first law of motion?
katrin2010 [14]
C) In the absence of an unbalanced force, an object at rest will stay at rest and an object in motion will stay in motion.

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8 0
3 years ago
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Bare free charges do not remain stationary when close together. To illustrate this, calculate the acceleration of two isolated p
Marta_Voda [28]

Answer:

Acceleration, a=9.91\times 10^{15}\ m/s^2

Explanation:

It is given that,

Separation between the protons, r=3.73\ nm=3.73\times 10^{-9}\ m

Charge on protons, q=1.6\times 10^{-19}\ C

Mass of protons, m=1.67\times 10^{-27}\ kg

We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :

ma=\dfrac{kq^2}{r^2}

a=\dfrac{kq^2}{mr^2}      

a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.67\times 10^{-27}\times (3.73\times 10^{-9})^2}      

a=9.91\times 10^{15}\ m/s^2

So, the acceleration of two isolated protons is 9.91\times 10^{15}\ m/s^2. Hence, this is the required solution.

3 0
3 years ago
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