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uranmaximum [27]
3 years ago
6

Please help!! This is about chemicals

Physics
1 answer:
svetoff [14.1K]3 years ago
3 0
A Is correct I believe
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A thin plastic rod of length 2.5 m is rubbed all over with wool, and acquires a charge of 75 nC, distributed uniformly over its
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find out the le

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3. Suppose you take a pendulum with length L and mass m having a period T to a
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(C)

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t = 2\pi \sqrt{ \frac{l}{g} }

If g is only 1/6 on another planet, then

t = 2\pi \sqrt{ \frac{l}{ \frac{g}{6} } } =  2\pi \sqrt{ \frac{6l}{g} }

=  \sqrt{6} \: (2\pi \sqrt{ \frac{l}{g} } ) = 2.4  \times t(on \: earth)

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Which statement describes the process of subduction? Convection currents pull a plate into the mantle. One plate slides beneath
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Potential difference is measured in units called
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A 2. 0 μf and a 4. 0 μf capacitor are connected in series across an 8. 0-v dc source. what is the charge on the 2. 0 μf capacito
Nezavi [6.7K]

voltage across 2.0μf capacitor is 5.32v

Given:

C1=2.0μf

C2=4.0μf

since two capacitors are in series there equivalent capacitance will be

[tex] \frac{1}{c} = \frac{1}{c1} + \frac{1}{c2} [/tex]

c =  \frac{c1 \times c2}{c1 + c2}

=  \frac{2 \times 4}{2 + 4}

=1.33μf

As the capacitance of a capacitor is equal to the ratio of the stored charge to the potential difference across its plates, giving: C = Q/V, thus V = Q/C as Q is constant across all series connected capacitors, therefore the individual voltage drops across each capacitor is determined by its its capacitance value.

Q=CV

given,V=8v

= 1.33 \times 10 {}^{ - 6}  \times 8

= 10.64 \times 10 {}^{ - 6}

charge on 2.0μf capacitor is

\frac{Qeq}{2 \times 10 {}^{ - 6} }

=  \frac{10.64 \times 10 {}^{ - 6} }{2 \times 10 {}^{ - 6} }

=5.32v

learn more about series capacitance from here: brainly.com/question/28166078

#SPJ4

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