Yes ur correct again hahaha
h = Vy t - 1/2 g t^2 = -1.07 m final height of ball relative to being hit
Vy = 37 * sin 53.1 = 29.6 m/s initial vertical velocity
h = 29.6 t - 9.8 /2 t^2
4.9 t^2 -29.6 t - 1.07 = 0
Solving the quadratic for t = 6.08 sec for time of flight
Vy - g t = 0 where t is time to reach max height
t = 29.6 / 9.8 = 3.02 sec to reach max height
S = Vx * t where t is the distance traveled
S = V0 cos 53.1 * 6.08 = 37 * .60 * 6.08 = 135 m about 443 ft
Newtons first law of motion
object in motion stays in motion, object at rest stays at rest unless acted upon an unbalanced force
Change in momentum over time.
