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3 years ago

In ABC, if m angle A

Mathematics

2 answers:

umka2103 [35]3 years ago

3 0

Answer:

what

Step-by-step explanation:

nordsb [41]3 years ago

3 0

Answer:

In ABC, if m angle A

Step-by-step explanation:

yes you are right

You might be interested in

Solution q-2r=4<br> q+r=37

GenaCL600 [577]

Q-2r=4, therefore: q=4+2r.

Plug the value of q into q+r=37, so you get:

4+2r+r=37

3r=37-4=33

3r=33

Therefore: r=11.

q-2r=4, but r=11, so:

q-2(11)=4

q-22=4

Therefore q=26.

Check if the answer is correct using second equation:

q=4+2r=4+2(11)=4+22=26.

So: q=26 and r=11.

4 0

3 years ago

Read 2 more answers

A 24,000-gallon pool is being filled at a rate of 50 gallons per minute. At this rate, how many minutes will it take to fill thi

ser-zykov [4K]

Answer:

192 minutes

Step-by-step explanation:

24,000 times .4 = 9600

9600 / 50 = 192

4 0

2 years ago

I need help with number 11

FinnZ [79.3K]

Answer:

-b/2a is the equation to find the x coordinate of the vertex point and it's y, when x is plugged into the quadratic equation.

Step-by-step explanation:

6 0

2 years ago

Given the functionf ( x ) = x^2 + 7 x + 10/ x^2 + 9 x + 20

vladimir1956 [14]

<em>x = -4 is a vertical asymptote for the function.</em>

<h2>Explanation:</h2>

The graph of $y=f(x)$ is a vertical has an asymptote at $x=a$ if at least one of the following statements is true:

$1) \ \underset{x\rightarrow a^{-}}{lim}f(x)=\infty\\ \\ 2) \ \underset{x\rightarrow a^{-}}{lim}f(x)=-\infty \\ \\ 3) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty \\ \\ 4) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty$

The function is:

$f(x)=\frac{x^2+7x+10}{x^2+9x+20}$

First of all, let't factor out:

$f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20} \\ \\ f(x)=\frac{x(x+5)+2(x+5)}{x(x+5)+4(x+5)} \\ \\ f(x)=\frac{(x+5)(x+2)}{(x+5)(x+4)} \\ \\ f(x)=\frac{(x+2)}{(x+4)}, \ x\neq 5$

From here:

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ right: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(-4^{+}+2)}{(-4^{+}+4)} \\ \\ \\ The \ numerator \ is \ negative \ and \ the \ denominator \\ is \ a \ small \ positive \ number. \ So: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=-\infty$

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ left: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(-4^{-}+2)}{(-4^{-}+4)} \\ \\ \\ The \ numerator \ is \ a \ negative \ and \ the \ denominator \\ is \ a \ small \ negative \ number \ too. \ So: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=+\infty$