Answer:
See figure 1 and 2
Explanation:
In this case, we can start with the general reaction. Acetanilide with bromine in acetic acid we will produce <u>p-bromo-acetanilide</u> (See figure 1).
In the reaction mechanism, we have as first step the attack of the double bond in the benzene ring to one of the Br atoms in bromine (
) and a positive carbon will be produced in benzene. This positive charge can be moved inside of the benzne ring producing the r<u>esonance structures A, B and D</u>. Resonance structure C is produced when a double bond is generating between the "N" atom and the carbon in the benzene ring.
The final step in the mechanism is when we remove the "H" atom in structure A to produce again the double bond.
See figure 2
I hope it helps!
FOLLOWING!!!!!!!!!!!!!!!!!!
The concentration of the HBr would be 0.09 M
<h3>What are stoichiometric problems?</h3>
First, let us look at the equation of the reaction:
The mole ratio of HBr to NaOH is 1:1.
Mole of 15 mL, 0.30 M NaOH = 0.30 x 15/1000 = 0.0045 moles
Equivalent mole of HBr - 0.0045 moles
Molarity of HBr = mole/volume = 0.0045/50/1000 = 0.09 M
More on stoichiometric problems can be found here: brainly.com/question/15047541
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False! Pure water does not contain salt and is a poor conductor
