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zavuch27 [327]
3 years ago
6

Write a mechanism for the bromination of acetanilide with bromine in acetic acid. Be as complete as possible and include all rel

evant resonance structures.

Chemistry
1 answer:
Karolina [17]3 years ago
4 0

Answer:

See figure 1 and 2

Explanation:

In this case, we can start with the general reaction. Acetanilide with bromine in acetic acid we will produce <u>p-bromo-acetanilide</u> (See figure 1).

In the reaction mechanism, we have as first step the attack of the double bond in the benzene ring to one of the Br atoms in bromine (Br_2) and a positive carbon will be produced in benzene. This positive charge can be moved inside of the benzne ring producing the r<u>esonance structures A, B and D</u>. Resonance structure C is produced when a double bond is generating between the "N" atom and the carbon in the benzene ring.

The final step in the mechanism is when we remove the "H" atom in structure A to produce again the double bond.

See figure 2

I hope it helps!

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Calculate the molarity and normality of 5.7 g of Ca(OH)2 in 450 mL of solution.
Kisachek [45]
  The  molarity   and  normality  of  5.7 g  of  Ca(OH)2   in  450ml  0f    solution  is  calculated  as  follows

molarity  =  moles/volume in  liters
moles  =mass/molar  mass
=  5.7g/74g/mol  =  0.077moles
molarity =  0.077/450  x1000= 0.17M

Normality =  equivalent  point  x molarity
equivalent  point  of Ca(OH)2  is  2   since  it has  two  Hydrogen  atom

normality  is therefore =  0.17  x2 = 0.34 N
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3 years ago
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svetlana [45]

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This is because the reactants are typically always on the left side of the yields symbol. In this decomposition reaction, it would still be the same as at the end of the reaction, there were to products produced: Mercury and Oxygen.

Products tend to always be on the right side of the yields symbol, they're what comes out of a reaction no matter what type.

Hope this helps!

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sweet [91]
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V125BC [204]

Answer:

\boxed{\text{amide groups}}

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