Raising the concentration of hydronium ions, H3O+, in a solution will result in the pH level _________.

Chemistry

1 answer:

algol [13]2 years ago

3 0

Answer:B) Going Down

Explanation:

The higher the concentration of hydro in ions in a solution, the more acidic it is, and the lower the pH is.

(I just answered the question on USA TP!)

You might be interested in

Oxygen's atomic number is 8. This means that an oxygen atom has

vladimir2022 [97]

Answer:

8 protons in its nucleus

5 0

2 years ago

Read 2 more answers

IF anyone didn't do this E D G E N U I T Y thing here you guys go pass it around to people that need help this is what it is cal

SashulF [63]

Answer:

<h2>My My name: CORN CORNELIUS CORNWALL</h2><h2>My Age: 209374329 years old</h2><h2>Fav song : Baby by justin bieber</h2><h2>most legendary thing that i got : club penguin membership</h2>

5 0

1 year ago

Find the equilibrium value of [CO] if Kc=14.5 : CO (g) + 2H2 (g) ↔ CH3OH (g) Equilibrium concentrations: [H2] = 0.322 M and [CH3

Annette [7]

Answer:

The equilibrium value of [CO] is 1.04 M

Explanation:

Chemical equilibrium is the state to which a spontaneously evolving chemical system, in which a reversible chemical reaction takes place. When this situation is reached, it is observed that the concentrations of substances, both reagents and reaction products, they remain constant over time. That is, the rate of reaction of reagents to products is the same as that of products to reagents.

Reagent concentrations and products in equilibrium are related by the equilibrium constant Kc. Being:

aA + bB ⇔ cC + dD

$Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }$

Then this constant Kces equals the multiplication of the concentrations of the products raised to their stoichiometric coefficients between the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients.

In this case:

$Kc=\frac{[CH_{3}OH ]}{[CO]*[H_{2} ]^{2} }$