Answer is: 550,021 kWh of energy is needed to heat the water
V(water) = 51 gal = 51·3,78 = 189,3 L.
ΔT(water) = 25°C.
d(water) = 1000 g/L.
m(water) = V(water) · d(water)
m(water) = 189,3 L · 1000 g/L
m(water) = 189300 g.
Q = m(water) · ΔT(water) · C(water)
Q = 189300 g · 25°C · 4,184 J/°C·g
Q = 19800780 J = 19800,78 kJ ÷ 3600 = 550,021 kWh.
<em>Answer:</em>
- The molarity of ammonia will be 2.88 M.
<em>Chemical equation</em>
HCl + NH3 ------> NH4Cl
First of calculate the moles of HCl
mole of HCl = Molarity × Vol (L)
mole of HCl = 0.800× 0.018 = 0.014 mole
As the in balance chemical, moles of HCl and NH3 areequal
so
moles of NH3= 0.014
Molarity of NH3 = moles ÷ V(L) = 0.014/0.005 = 2.88 M
<em>Result</em>:
- The molarity of ammonia will be 2.88 M.
You would divide the number of atoms by Avogadro's number [6.02x10^23]
Answer:
615 μK/ms.
Explanation:
The conversion of 615mK/s to μK/ms can be obtained as follow:
1 mK/s = 10^-3 K/s
Therefore, 615mK/s = 615x10^-3 K/s
1K/s = 10^6 μK/s
Therefore,
615x10^-3 K/s = 615 x 10^-3 x 10^6 μK/s = 615x10^3 μK/s.
1s = 10^3ms
Therefore,
615x10^3 μK/s = 615x10^3 μK/ 10^3ms = 615 μK/ms.
Therefore,
615 mK/s = 615 μK/ms.
Cl (chloride) have negative charge Cl-, and it's called an anion bcz when an atom gains one or more electrons, a negative ion is formed, which makes the atom has more electrons than protons.
