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disa [49]
3 years ago
9

For each system listed in the first column of the table below, decide (if possible) whether the change described in the second c

olumn will increase the entropy S of the system, decrease S, or leave S unchanged. If you don’t have enough information to decide, check the “not enough information “button in the last column.

Chemistry
1 answer:
kiruha [24]3 years ago
4 0

Answer:

For each system listed in the first column of the table below, decide (If possible) whether the change described in the second column will Increase the entropy S of the system, decrease S, or leave S unchanged. If you don't have enough information to decide, check the not enough information" button in the last column.

System As A few grams of water vapor (H,0). The water condenses to a liquid at a not enough The carbon dioxide is heated from -5.0 °C to 13.0°c and is also compressed from a volume of 9.0 1 to a volume of 5.0L A few moles of carbon dioxide (CO2) gas. not enough information -15.0 °C to 86.0 °C while the volume is held constant at 2.0 L A few moles of carbon dioxide (CO,) gas. S > 0 not enough 1 Don't Know

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Does heating a cup of water allow it to dissolve more sugar? Temperature of the water is measured in degrees centigrade. Amount
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Answer:

Yes

Explanation:

Yes heating water allows it to dissolve more Sugars because the molecular distance increases and this distance can be covered by more sugar. In the given question, The independent variable would be the temperature of water.

Since to whatever temperature the water boils at the boiling temperature of  does not change remains hundred degree. Rest all the variables can vary the weight of the amount of sugar with the variable in the temperature of Boiling of water to remain constant.

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When you have a free metal ion, how do the energies of these orbitals relate to one another (are they the same, different, etc.)
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The energy of the orbitals are the same

Explanation:

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Which characteristic(s) makes a compounds useful as a building material?
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3 0
3 years ago
7.0 mol Mn reacts with 5.0 mol
Elenna [48]

The moles of MnO formed with the reaction of 5 moles of Mn is 3 moles.

<h3>What is a limiting reagent?</h3><h3 />

In a chemical reaction, the reagent that is present in a lesser quantity and governs the rate of the reaction is termed as the limiting reagent.

In the reaction of the formation of MnO, according to the stoichiometric law 2 moles of Mn reacts with 1 moles of Oxygen.

Thus, the moles of oxygen consumed by 7 moles of Mn is:

2 moles Mn = 1 mole O₂

7 moles Mn = 3.5 moles O₂

The available moles of O₂ = 5 mol.

The remaining moles of O₂ = 5-3.5 moles

The remaining moles of O₂ = 1.5 moles

The reaction of 5 moles Mn requires 2.5 moles of O₂, whereas the available moles of oxygen is 1.5 moles. Thus, oxygen serves as the limiting reagent.

The moles of MnO formed with the reaction of 5 moles Mn and 1.5 moles O₂

1 mole O₂ = 2 moles MnO

1.5 moles O₂ = 2 * 1.5 moles MnO

1.5 moles O₂ = 3 moles MnO

Thus, the moles of MnO formed with the reaction of 5 moles of Mn with the available oxygen is 3 moles.

Learn more about stoichiometric law, here:

brainly.com/question/14465605

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6 0
1 year ago
Read 2 more answers
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