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AlexFokin [52]
4 years ago
15

A student adds 4.00g of dry ice (solid CO2) to an empty balloon. What will be the volume of the balloon at STP after all the dry

ice sublimes (converts to gaseous CO2)
Chemistry
1 answer:
kondaur [170]4 years ago
5 0

Answer : The volume of the balloon at STP is, 2.04 L

Explanation :

First we have to calculate the moles of dry ice.

\text{Moles of dry ice}=\frac{\text{Mass of dry ice}}{\text{Molar mass of dry ice}}

Molar mass of dry ice (CO_2) = 44 g/mol

\text{Moles of dry ice}=\frac{4.00g}{44g/mol}=0.0909mol

Now we have to calculate the volume of dry ice.

As we know that 1 mole of substance contains 22.4 L volume of gas.

As, 1 mole of dry ice contains 22.4 L volume of gas.

So, 0.0909 mole of dry ice contains 0.0909 × 22.4 L = 2.04 L volume of gas.

Thus, the volume of the balloon at STP is, 2.04 L

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3 years ago
Find the percent composition of OXYGEN in Manganese (III) nitrate, Mn(NO3)3.
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Answer:

59.8%

Explanation:

First find the Mr of manganese (III) nitrate.

Mr of Mn(NO₃)₃ = 54.9 + (14 × 3) + (16 × 3 × 3) = <u>240.9</u>

Since we have to find the percentage composition of oxygen, we need to find the Mr of oxygen in the compound, which is:

Mr of (O₃)₃ = (16 × 3) × 3 = <u>144</u>

Now we can find percentage composition / percentage by mass of oxygen.

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Answer:

13.53 kJ

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