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AlexFokin [52]
3 years ago
15

A student adds 4.00g of dry ice (solid CO2) to an empty balloon. What will be the volume of the balloon at STP after all the dry

ice sublimes (converts to gaseous CO2)
Chemistry
1 answer:
kondaur [170]3 years ago
5 0

Answer : The volume of the balloon at STP is, 2.04 L

Explanation :

First we have to calculate the moles of dry ice.

\text{Moles of dry ice}=\frac{\text{Mass of dry ice}}{\text{Molar mass of dry ice}}

Molar mass of dry ice (CO_2) = 44 g/mol

\text{Moles of dry ice}=\frac{4.00g}{44g/mol}=0.0909mol

Now we have to calculate the volume of dry ice.

As we know that 1 mole of substance contains 22.4 L volume of gas.

As, 1 mole of dry ice contains 22.4 L volume of gas.

So, 0.0909 mole of dry ice contains 0.0909 × 22.4 L = 2.04 L volume of gas.

Thus, the volume of the balloon at STP is, 2.04 L

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Answer:

  • 2SO₂ +  O₂ + 2H₂O  -----------> 2H₂SO₄
  • Theoretical yield of H₂SO₄ = 213 g
  • percent yield of H₂SO₄ = 94 %  

Explanation:

Data Given:

volume of SO₂ = 48.6 L

mass of H₂SO₄ = 200 g

balance equation = ?

theoretical yield = ?

percent yield = ?

Solution:

Part 1:

first we have to write a balance equation for the reaction

SO₂ gas react with water (H₂O) and excess oxygen

The balanced equation is as under

                       2SO₂ +  O₂ + 2H₂O  -----------> 2H₂SO₄

Part 2:

Now we have to find theoretical yield

First look at the balance reaction

                        2SO₂ +  O₂ + 2H₂O  -----------> 2H₂SO₄

                        2 mol                                         2 mol

2 moles of SO₂ give gives 2 moles of H₂SO₄

Now calculate volume of 2 moles of SO₂ and mass of 2 moles of H₂SO₄

volume of 2 moles of SO₂

Formula used

                 volume of gas = no. of moles x molar volume . . . . . . (1)

molar volume of SO₂= 22.4 L/mol

Put values in above formula (1)

                 volume of gas = 2 mol x 22.4 L/mol

                 volume of gas = 44.8 L

volume of 2 mole of SO₂ = 44.8 L

Now,

Find mass of 2 mole H₂SO₄

Formula Used

            mass in grams = no. of moles x molar mass . . . . . . . (2)

molar mass of H₂SO₄ = 2 (1) + 32 + 4(16)

molar mass of H₂SO₄ = 98 g/mol

put values in equation 2

        mass in grams = 2 mol x 98 g/mol

        mass in grams = 196 g

mass of 2 mole of H₂SO₄ = 196 g

** So,

Now we come to know that

44.8 L of SO₂ gives 196 g of H₂SO₄ then how many grams of the H₂SO₄ will be produced by 48.6 L of SO₂

Apply unity Formula

               44.8 L of SO₂ ≅ 196 g of H₂SO₄

               48.6 L of SO₂ ≅ X g of H₂SO₄

Do cross multiplication

                g of H₂SO₄  = 196 g x 48.6 L / 44.8 L

                g of H₂SO₄  =  213 g

So that is why the theoretical yield of H₂SO₄ is 213 g

Theoretical yield of H₂SO₄ = 213 g

Part 3

Calculate Percent Yield:

Formula used for this purpose:

             percent yield = actual yield /theoretical yield x 100 %

Put value in the above formula

           percent yield = 200 g/ 213 g x 100 %

          percent yield = 94 %    

So percent yield of H₂SO₄ = 94 %    

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Elements are defined as the smallest substances which cannot be broken down into another substance by any chemical means.

A compound is a defined as a substance composed of two or more different elements when they combine chemically in definite proportion. For example: CO_2 is named as carbon dioxide and is a compound made by combining carbon and oxygen in a fixed ratio of 1 : 2

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