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AlexFokin [52]
4 years ago
15

A student adds 4.00g of dry ice (solid CO2) to an empty balloon. What will be the volume of the balloon at STP after all the dry

ice sublimes (converts to gaseous CO2)
Chemistry
1 answer:
kondaur [170]4 years ago
5 0

Answer : The volume of the balloon at STP is, 2.04 L

Explanation :

First we have to calculate the moles of dry ice.

\text{Moles of dry ice}=\frac{\text{Mass of dry ice}}{\text{Molar mass of dry ice}}

Molar mass of dry ice (CO_2) = 44 g/mol

\text{Moles of dry ice}=\frac{4.00g}{44g/mol}=0.0909mol

Now we have to calculate the volume of dry ice.

As we know that 1 mole of substance contains 22.4 L volume of gas.

As, 1 mole of dry ice contains 22.4 L volume of gas.

So, 0.0909 mole of dry ice contains 0.0909 × 22.4 L = 2.04 L volume of gas.

Thus, the volume of the balloon at STP is, 2.04 L

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100 points+Brainliest for correct answer
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O Option 1

Explanation:

IF ENERGY IS RELEASED, THEN ENERGY RELEASED SHOULD BE SUBTRACTED FROM ORIGINAL.

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6 0
2 years ago
Read 2 more answers
A sample of TNT, C7H5N3O6 , has 8.94 × 1021 nitrogen atoms. How many hydrogen atoms are there in this sample of TNT?
Bess [88]

Answer:

1.49×10²² atoms of H are contained in the sample

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TNT → C₇H₅N₃O₆

1 mol of this has 7 moles of C, 5 moles of H, 3 moles of N and 6 moles of O

Let's determine the mass of TNT.

Molar mass is = 227 g/mol

As 1 mol has (6.02×10²³) NA atoms, how many moles are 8.94×10²¹ atoms.

8.94×10²¹ atoms / NA = 0.0148 moles

So this would be the rule of three to determine the mass of TNT

3 moles of N are in 227 g of compound

0.0148 moles of N are contained in (0.0148 .227) / 3 = 1.12 g

Now we can work with the hydrogen.

227 grams of TNT contain 5 moles of H

1.12 grams of TNT would contain (1.12 .5) / 227 = 0.0247 moles

Finally let's convert this moles to atoms:

0.0247 mol . 6.02×10²³ atoms / 1 mol = 1.49×10²² atoms

8 0
3 years ago
Planting more vegetation will result in __________ erosion. decreased increased the same can't tell
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6 0
4 years ago
For the reaction 2NOCl(g) <-----> 2NO(g) + Cl2(g), Kc = 8.0 at a certain temperature. What concentration of NOCl must be p
Nat2105 [25]
Answer is: <span>concentration of NOCl is 3.52 M.
</span>
Balanced chemical reaction: 2NOCl(g) ⇄ 2NO(g) + Cl₂<span>(g).
Kc = 8.0.
</span>[NOCl] = 1.00 M; equilibrium concentration.
[NO] = x.
[Cl₂] = x/2; equilibrium concentration of chlorine.<span>
Kc = </span>[Cl₂] ·[NO]² / [NOCl].
8.00 = x/2 · x² / 1.
x³/2 = 8.
x = ∛16.
x = 2.52 M.
co(NOCl) = [NOCl] + x.
co(NOCl) = 1.00 M + 2.52 M.
co(NOCl) = 3.52 M; the initial concentration of NOCl.


7 0
3 years ago
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