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2 years ago

What is the percent composition of nitrogen in sodium nitride

Chemistry

1 answer:

Neporo4naja [7]2 years ago

5 0

Answer:

16.86%

Explanation:

Na3N is sodium nitride.

% of N = mass of N/ molar mass of Na3N *100

% of N = 14/83*100= 16.86%

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In this question,

The initial volume of the gas is $V_1= 256\; \rm mL$ .
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The goal is to find the new pressure of this gas, $P_2$ .

Assume that this sample is indeed an ideal gas. Then the equation $P_1 \cdot V_1 =P_2 \cdot V_2$ should still hold. Rearrange the equation to separate the unknown, $P_2$ . Note: make sure that the units for $V_1$ and $V_2$ are the same before evaluating. That way, the unit of

$\begin{aligned} & P_2\\ &= \frac{P_1 \cdot V_1}{V_2} \\ &= \frac{256\; \rm mL \times 67.5\; \rm mmHg}{135\; \rm mL} \\ & \approx 128\; \rm mmHg\end{aligned}$ .

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