A car travels for 50mph for 5 hours, then for 30mph for another 3 hours in the same direction. What is the average speed the mot
1 answer:
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Answer:
sin 2θ = 1 θ=45
Explanation:
They ask us to prove that the optimal launch angle is 45º, for this by reviewing the parabolic launch equations we have the scope equation
R = Vo² sin 2θ / g
Where R is the horizontal range, Vo is the initial velocity, g the acceleration of gravity and θ the launch angle. From this equation we see that the sine function is maximum 2θ = 90 since sin 90 = 1 which implies that θ = 45º; This proves that this is the optimum angle to have the maximum range.
We calculate the distance traveled for different angle
R = vo² Sin (2 15) /9.8
R = Vo² 0.051 m
In the table are all values in two ways
Angle (θ) distance R (x)
0 0 0
15 0.051 Vo² 0.5 Vo²/g
30 0.088 vo² 0.866 Vo²/g
45 0.102 Vo² 1 Vo²/g
60 0.088 Vo² 0.866 Vo²/g
75 0.051 vo² 0.5 Vo²/g
90 0 0
See graphic ( R Vs θ) in the attached ¡, it can be done with any program, for example EXCEL
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
b
New
Explanation:
From the question we are told that
The refractive index of the core is
The refractive index of the cladding is
Generally according to Snell's law
Where is the largest angle a largest angle a ray will make with respect to the interface of the fiber and experience total internal reflection
Given from the question the the largest angle is 5°
Generally the refraction index of the cladding is mathematically represented as
