Answer:
x = 1/3 + sqrt(5/2)/3 or x = 1/3 - sqrt(5/2)/3
Step-by-step explanation:
Solve for x:
6 x^2 - 4 x = 1
Divide both sides by 6:
x^2 - (2 x)/3 = 1/6
Add 1/9 to both sides:
x^2 - (2 x)/3 + 1/9 = 5/18
Write the left hand side as a square:
(x - 1/3)^2 = 5/18
Take the square root of both sides:
x - 1/3 = sqrt(5/2)/3 or x - 1/3 = -sqrt(5/2)/3
Add 1/3 to both sides:
x = 1/3 + sqrt(5/2)/3 or x - 1/3 = -sqrt(5/2)/3
Add 1/3 to both sides:
Answer: x = 1/3 + sqrt(5/2)/3 or x = 1/3 - sqrt(5/2)/3
<span>We have 75 mL of 4% sugar solution.
We have to add a 30% sugar </span><span>solution to make a 50% </span><span>sugar solution.
75 * .04 + .30x = .50 * (75 +x)
3 + .30x = 37.5 +.50x
I can't get the equation to solve.
Did you type it correctly? For one thing, you have the percentages typed as .30 % and 4%. Are the decimal places in the correct positions?
Also, no matter how much 30% sugar solution you add, it will NEVER increase to 50%.
</span>
The correct answer is 11.3
Answer: h(x) = 3*x^2 - 7*x + 8
Step-by-step explanation:
The rate of change of a function is equal to the derivate:
remember that a derivate of the form:
k(x) = a*x^n is k'(x) = n*a*x^(n-1)
Then we have:
f(x) = 2*x - 10
f'(x) = 1*2* = 2
g(x) = 16*x - 4
g'(x) = 1*16 = 16
h(x) = 3*x^2 - 7*x + 8
h'(x) = 2*3*x - 1*7 = 6*x - 7
So the only that increases as x increases is h(x), this means that the greates rate of change as x approaches inffinity is the rate of change of h(x)
Answer:
Step-by-step explanation:
we know that
----> by supplementary angles (form a linear pair)
Solve for x
Combine like terms
subtract 99 both sides
Divide by 3 both sides
