The Length of FD = 26 cm
According to the given information
FE = FC = 12cm
As FE, FC both are radius of circle
The tangent segments to a circle from a external point are equal
Hence
CD = ED
13x - 16 = 4x + 11
13x - 4x = 11 + 16
9x = 27
x = 27/9
x = 3
CD = 13x - 16
= 13 × 3 - 16
= 23 cm
ED = 4x + 11
= 4 × 3 + 11
= 23 cm
In Triangle FED
FE is perpendicular to ED
According to Pythagoras Theorem
![FD^{2}= FE^{2}+ED^{2}](https://tex.z-dn.net/?f=FD%5E%7B2%7D%3D%20FE%5E%7B2%7D%2BED%5E%7B2%7D)
= ![12^{2}+ 23^{2}](https://tex.z-dn.net/?f=12%5E%7B2%7D%2B%2023%5E%7B2%7D)
= 673
FD = 26 cm approx.
The Length of FD = 26 cm
To know more about Pythagoras Theorem
brainly.com/question/343682
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Answer:
![x=-3\:or\:x=\frac{3}{2}](https://tex.z-dn.net/?f=x%3D-3%5C%3Aor%5C%3Ax%3D%5Cfrac%7B3%7D%7B2%7D)
Step-by-step explanation:
The given parabola has equation
![2x^2+5x-9=2x](https://tex.z-dn.net/?f=2x%5E2%2B5x-9%3D2x)
We rewrite in standard form to obtain:
![2x^2+5x-2x-9=0](https://tex.z-dn.net/?f=2x%5E2%2B5x-2x-9%3D0)
![2x^2+3x-9=0](https://tex.z-dn.net/?f=2x%5E2%2B3x-9%3D0)
Split the middle terms to get:
![2x^2+6x-3x-9=0](https://tex.z-dn.net/?f=2x%5E2%2B6x-3x-9%3D0)
Factor by grouping:
![2x(x+3)-3(x+3)=0](https://tex.z-dn.net/?f=2x%28x%2B3%29-3%28x%2B3%29%3D0)
![(x+3)(2x-3)=0](https://tex.z-dn.net/?f=%28x%2B3%29%282x-3%29%3D0)
![x=-3\:or\:x=\frac{3}{2}](https://tex.z-dn.net/?f=x%3D-3%5C%3Aor%5C%3Ax%3D%5Cfrac%7B3%7D%7B2%7D)
Answer:
3 3/4
Step-by-step explanation:
First off, the area of the circle would be 78.54
Now, you would do (area of the triangle)--- AT-78.54=answer
I don't know how to find the area of the triangle with just the circle's radius, so this is all I can do. I'm sorry!