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jonny [76]
3 years ago
14

Pls help due soon. ​

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
7 0
The answer is 54

(i took the quiz and got it correct)
Paladinen [302]3 years ago
3 0

Answer:

54

Step-by-step explanation:

\frac{1}{2}base \times height

\frac{1}{2} 12 \times 9

54

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(5x)/7 - x/14 = 9/7 solve for the unknown value this is a linear equation​
Ahat [919]

Step-by-step explanation:

\longmapsto \rm \dfrac{5x}{7} - \dfrac{x}{14} = \dfrac{9}{7} \\

\longmapsto \rm  \dfrac{10x + x}{14} = \dfrac{9}{7} \\

\longmapsto \rm  \dfrac{11x}{14} = \dfrac{9}{7} \\

→ 11x(7) = 14(9)

→ 77x = 126

→ x = 126 ÷ 77

→ x = 1.63

7 0
3 years ago
What is 18.25 as a fraction ?
Elis [28]
73/4 is the answer to your question sir your welcome
7 0
3 years ago
Read 2 more answers
What is the height of a triangle if the side is 26ft and the base is 10ft
Kisachek [45]

Answer:

65ft

Step-by-step explanation:


7 0
3 years ago
Factor the expression 2x^3-10x^2-5x+25. Show your work.
azamat

Step 1. Factor out common terms in the first two terms, then in the last two terms.

2x^2(x - 5) -5(x - 5)

Step 2. Factor out the common term x - 5

(x - 5)(2x^2 - 5)

4 0
3 years ago
The grade you make on your exam varies directly with the number of correct answers you get on the exam.Answering 15 questions co
yuradex [85]

<u>Answer:</u>

The grade you make on your exam varies directly with the number of correct answers. The constant of variation is 5

<u>Solution:</u>

Given, The grade you make on your exam varies directly with the number of correct answers you get on the exam.  

Answering 15 questions correctly will give you a grade of 75 what is the.  

We have to find what is the Constant of variation.

Now, according to the given information, grade  number of correct answer  

Then, grade = c x number of correct answers, where c is constant of variation.

Now, substitute grade = 75 and number of correct answers = 15

\text { Then, } 75=c \times 15 \rightarrow c=\frac{75}{15}=5

Hence, the constant of variation is 5

5 0
3 years ago
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