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Reika [66]
3 years ago
15

Solve the linear system of equations using the linear combination method.

Mathematics
1 answer:
Mrrafil [7]3 years ago
6 0

Answer:

x=-4

y=-4

Step-by-step explanation:

We are going to eliminate the variable x. In order to do this, we are going to make the coefficients the same by multiplying the second equation by 2

mark brainliest  :)

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What is the total are of 3/4 multiplied by 3/4?
notsponge [240]
3/4*3/4 = (3*3)/(4*4) = 9/16
6 0
2 years ago
I need help asap someone please help me i dont understand this question so can someone help me
eduard

Answer:

we conclude that:

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}

Step-by-step explanation:

Given the expression

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}

=\frac{2p}{4p^2-1}\times \frac{6p+3}{6p^3}

=\frac{2p}{4p^2-1}\times \frac{2p+1}{2p^3}

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

=\frac{2p\left(2p+1\right)}{\left(4p^2-1\right)\times \:2p^3}

cancel the common factor: 2

=\frac{p\left(2p+1\right)}{\left(4p^2-1\right)p^3}

cancel the common factor: p

=\frac{2p+1}{p^2\left(4p^2-1\right)}

=\frac{2p+1}{p^2\left(2p+1\right)\left(2p-1\right)}

cancel the common factor: 2p+1

=\frac{1}{p^2\left(2p-1\right)}

Expanding

=\frac{1}{2p^3-p^2}

Thus, we conclude that:

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}

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3 years ago
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astraxan [27]
The bridge attached is drawn according to given dimensions, and it doesn't look right.  Please double check the given dimensions.

Calculations:
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= 15.1*sin(70) = 14.19
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Therefore 
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4 0
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3 years ago
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