1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alexandra [31]
3 years ago
12

Giving 20 points and brainiest But please help me

Physics
1 answer:
monitta3 years ago
8 0

Answer:

yeah, Do you want me to check your answers? Yes is correct

You might be interested in
When do we experience conservation of energy
Lerok [7]

Always, whether we notice it or not. It's a law of nature.

4 0
3 years ago
A surface receiving sound is moved from its original position to a position three times farther away from the source of the soun
vazorg [7]

Answer:

c. nine times as low.

Explanation:

Sound intensity is defined as the acoustic power transferred by a sound wave per unit of normal area to the direction of propagation:

I\propto \frac{1}{A}

Since the sound wave has a spherical wavefront of radius r, then the area is given by:

A=4\pi r^2

Here r is the distance from the source of the sound. Thus sound intensity decreases as:

I\propto \frac{1}{4\pi r^2}\\\\I'\propto \frac{1}{4\pi r'^2}\\\\I'\propto \frac{1}{4\pi (3r)^2}\\\\I'\propto \frac{1}{9} \frac{1}{4\pi r^2}\\\\I'\propto \frac{1}{9} I

6 0
3 years ago
A car accelerates from zero to a speed of 110
Verizon [17]

The car's rate of  acceleration : a = 2.04 m/s²

<h3>Further explanation</h3>

Given

speed = 110 km/hr

time = 15 s

Required

The acceleration

Solution

110 km/hr⇒30.56 m/s

Acceleration is the change in velocity over time

a = Δv : Δt

Input the value :

a = 30.56 m/s : 15 s

a = 2.04 m/s²

3 0
3 years ago
A person has a gravitational force (weight) of 600 N on Earth. Suppose the mass of the Earth is double and the radius shrinks to
Alenkasestr [34]

Explanation:

that's impossible,the radius of the earth can't decrease when the mass doubles!

4 0
3 years ago
A uniform stick 1.5 m long with a total mass of 250 g is pivoted at its center. A 3.3-g bullet is shot through the stick midway
Andru [333]

Answer:

<em>63.44 rad/s</em>

<em></em>

Explanation:

mass of bullet = 3.3 g = 0.0033 kg

initial velocity of bullet v_{1} = 250 m/s

final velocity of bullet v_{2} = 140 m/s

loss of kinetic energy of the bullet = \frac{1}{2}m(v^{2} _{1} - v^{2} _{2})

==> \frac{1}{2}*0.0033*(250^{2}  - 140^{2} ) = 70.785 J

this energy is given to the stick

The stick has mass = 250 g =0.25 kg

its kinetic energy = 70.785 J

from

KE = \frac{1}{2} mv^{2}

70.785 = \frac{1}{2}*0.25*v^{2}

566.28 = v^{2}

v= \sqrt{566.28} = 23.79 m/s

the stick is 1.5 m long

this energy is impacted midway between the pivot and one end of the stick, which leaves it with a radius of 1.5/4 = 0.375 m

The angular speed will be

Ω = v/r = 23.79/0.375 =<em> 63.44 rad/s</em>

5 0
3 years ago
Other questions:
  • How can astronomers infer wich elements are found in a star
    7·2 answers
  • Why are the action and reaction forces described by Newton’s third law of motion excluded in the free-body diagram of an object?
    5·2 answers
  • What is the name of the process that involves a strong attractive force that keeps atoms together
    7·2 answers
  • An ideal spring obeys hooke's law: f = −bikx. a mass of m = 0.3 kg hung vertically from this spring stretches the spring 0.13 m.
    14·1 answer
  • Three blocks are arranged in a stack on a frictionless horizontal surface. The bottom block has a mass of 37.0 kg. A block of ma
    9·1 answer
  • A. Water has many unique properties. Identify a property of water and explain why this property makes water vital to living orga
    5·1 answer
  • How are speed and velocity similar ?
    9·2 answers
  • 50 Points!
    7·2 answers
  • 4.
    13·1 answer
  • Between the ball and the player's head, there are forces. Which of Newton's laws does this represent? Support your choice.
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!