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2 years ago

7

How does the mass of an object change when it acquires a positive charge? 1. decreases 2. more information is needed. 3. increas

es 4. doesn't change?

1 answer:

Reika [66]2 years ago

8 0

1. Decreases

To make something positive you remove electrons so it decreases

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A truck is traveling due north at 50 km/hr approaching a crossroad. On a perpendicular road a police car is traveling west towar

kirill [66]

Answer: $45\hat{i}+50\hat{j}$

Explanation:

Truck velocity=50 km/hr

police car velocity =45 km/hr

Let they start at t=0 s

After one hour

truck displacement $=50\times 1=50 km$

In vector Form $(r_1)=50\hat{j}$

For Police car displacement $=45\times 1=45 km$

in vector form $(r_2)=-45\hat{i}$

$r_{12}=50\hat{j}-(-45\hat{i})$

$r_{12}=45\hat{i}+50\hat{j}$

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If youre walking from point a to b, the magnitude of your displacement will always be equal or less than or greater than your di

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The magnitude of your displacement can be equal to the distance you covered, or it can be less than the distance you covered. But it can never be greater than the distance you covered.

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2 years ago

Which best esplains how the body maintains homeostasis.

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Read 2 more answers

A square wave has amplitude 0 V for the low voltage and 4 V for the high voltage. Calculate the average voltage by integrating o

Margarita [4]

Answer:

V_{average} = $\frac{1}{2} V_o$ , V_{average} = 2 V

Explanation:

he average or effective voltage of a wave is the value of the wave in a period

V_average = ∫ V dt

in this case the given volage is a square wave that can be described by the function

V (t) = $\left \{ {{V=V_o \ \ \ t< \tau /2} \atop {V=0 \ \ \ \ t> \tau /2 } } \right.$

to substitute in the equation let us separate the into two pairs

V_average = $\int\limits^{1/2}_0 {V_o} \, dt + \int\limits^1_{1/2} {0} \, dt$

V_average = $V_o \ \int\limits^{1/2}_0 {} \, dt$

V_{average} = $\frac{1}{2} V_o$

we evaluate V₀ = 4 V

V_{average} = 4 / 2)

V_{average} = 2 V

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2 years ago