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lutik1710 [3]
3 years ago
5

A war wolf is a device used during the middle ages to assault fortifications with large rocks. A simple trebuchet is constructed

with a large, stiff 4.1 m rod (assume it has negligible mass) with a heavy object of mass 52 kg and 14 cm from the axle around which the device pivots and a cup on the far end that holds the rock. The war wolf is loaded when it is in a horizontal position, and the rock is projected horizontally when after it has rotated to a vertical position. If the rock has a mass of 123 g, how fast (linear speed) does it move when launched?

Physics
1 answer:
Katarina [22]3 years ago
3 0

Answer:v=41.23 m/s

Explanation:

Given

mass of heavy object m_1=52 kg

distance of m_1 from the axle r_1=14 cm

mass of rock m_2=123 gm

Length of rod =4.1 m

distance of m_2 from axle r_2=4.1-0.14=3.96 m

Net torque acting is

T_{net}=m_1gr_1-m_2gr_2

T_{net}=52\times 0.14\times g-0.123\times 3.96\times g

T_{net}=6.793\times 9.8

T_{net}=66.57 N-m

Work done by T_{net} is converted to rock kinetic Energy

thus

T_{net}\times \theta =\frac{mv^2}{2}

Where \theta =angle\ turned =\frac{\pi }{2}

v= velocity\ at\ launch

66.57\times \frac{\pi }{2}=\frac{0.123\times v^2}{2}

v^2=66.57\times \pi

v=\sqrt{1700.511}

v=41.23 m/s

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