Answer:
Not doubled
Explanation:
The equation below represent the ideal gases relationship
PV ÷ T = constant
Here
P denotes pressure,
V denotes volume,
T denotes temperature in degrees Kelvin
Now
20 ° c = 273 + 20
= 293 K
And,
40 ° c = 313 K
So,
V = Vo. 313 K ÷ 293 K = 1.07 Vo
So, the volume is NOT doubled.
In the case when the temperature would be determined in degrees celsius at 0 degrees so the volume would be zero
<h3>
Answer:</h3>
12 years
<h3>
Explanation:</h3>
We are given;
Half life of hydrogen-3 is 12 years
Initial mass of Hydrogen-3 is 20 grams
Final mass will be 10 g because we are told half of the sample will decay.
To find the time taken for the decay we need to know what half life is;
- Half life is the time taken for a radioactive isotope to decay to half its original amount.
Remaining mass = Original mass × 0.5^n
n = number of half lives
therefore;
10 g = 20 g × 0.5^n
0.5 = 0.5^n
n = log 0.5 ÷ log 0.5
= 1
But, 1 half life is 12 years
Therefore, the time taken is 12 years
The correct answer would be B: 4.
The blank space in the task statement should be filled with 25 as methane can retain 25 times more heat than carbon dioxide.
<h3>Heat Retention: Methane and Carbon dioxide</h3>
Methane, carbon dioxide amongst other gases are important greenhouse gases which allows the Earth retain it's heat in order for it to be habitable.
Methane can retain and release about 25 times more heat than Carbon Dioxide although Methane emissions are lower compared to Carbon Dioxide.
Read more on Greenhouse Gases:
brainly.com/question/1878123
<u>Answer:</u> The change in enthalpy for the given system is -642.8 kJ/mol
<u>Explanation:</u>
To calculate the change in enthalpy for given Gibbs free energy, we use the equation:
where,
= Gibbs free energy = -717.5 kJ/mol = -717500 J/mol (Conversion factor: 1 kJ = 1000 J)
= change in enthalpy = ?
T = temperature = 337 K
= change in entropy = 221.7 J/mol.K
Putting values in above equation, we get:
Hence, the change in enthalpy for the given system is -642.8 kJ/mol
