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Mumz [18]
2 years ago
12

How many times does the Moon rotate on its axis during a lunar month?

Chemistry
1 answer:
ELEN [110]2 years ago
4 0

Answer:

one

Explanation:

im sure its one

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Appropriate units for the speed of a chemical reaction, the reaction rate, are _______.
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Appropriate units for the speed of a chemical reaction, the reaction rate, are M/s
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question #5: corals are sensitive to temperature . if temperatures are raised , it will cause the coral to bleach . what does bl
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coral bleaching is when the temperature of the water changes (even slight changes in temperature effect coral) and the coral reacts negatively to it causing it to die. unfortunately corals cannot recover once they have been bleached.  

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Help me I hate science so much​
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it would be sciemce

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8 0
2 years ago
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What is the answers and pls show work if possible!!
taurus [48]

D = m / V


It even gives you the density of gold in the problem. Major hint. Once you know the volume (using V = m / D) then you can calculate the height (thickness) from the equation...


V = L x W x H

Volume = Length x Width x Height


start by converting 200.0 mg into grams

1000 mg = 1 g

200. mg x (1 g / 10^3 mg) = 0.200 g


V = m / D

V = 0.200 g / (19.32 g/cm^3)

V = 0.01035 cm^3


Convert 2.4 ft and 1 ft to cm

2.4 ft x (12 in / 1 ft) x (2.54 cm / 1 in) = 73.15 cm

1 ft = 30.48 cm


Compute the height (thickness)

V = LxWxH

H = V / LW = 0.01035 cm^3 / 73.15 cm / 30.48 cm

H = 4.64 x 10^-6 cm


Convert to nanometers

4.64 x 10^-6 cm x (1 m / 100 cm) x (10^9 nm / 1 m) = 46.4 nm


Knowing the atomic radius of gold, I might have asked my students for the minimum number of gold atoms in this thickness of gold. This would assume that the gold atoms are all in a row. This would give the minimum number of gold atoms.


Atomic radius gold = 174 pm

Diameter = 348 pm


46.4 nm x (1 m / 10^9 nm) x (10^12 pm / 1 m) x (1 Au atom / 248 pm) = 133 atoms of gold


4 0
3 years ago
Suppose a platinum atom in the oxidation state formed a complex with two chloride anions and two ammonia molecules. Write the ch
Blababa [14]

Answer: Pt(Cl)2(NH3)2

Explanation:

In the formation of the complex, the oxidation number of platinum is plus two (+2) and two chloride ions cancel it out by their oxidation number of -1 each. Hence the complex has an overall charge of zero. It is thus neutral with no charge attached to its formula.

3 0
3 years ago
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