Answer:
17.78g
Explanation:
m/M = C×V
m/101.102= 0.7× 0.25
m= 101.102×0.7×0.25= 17.78g
A model showing that gases are made from the matter of particles that are too small to see and are moving freely around in space can explain many observations.
<h3>
Answer:</h3>
382.63 K
<h3>
Explanation:</h3>
We are given;
- Volume of Iodine as 71.4 mL
- Mass of Iodine as 0.276 g
- Pressure of Iodine as 0.478 atm
We are required to calculate the temperature of Iodine
- We are going to use the ideal gas equation;
- According to the ideal gas equation; PV = nRT, where R is the ideal gas constant, 0.082057 L.atm/mol.K.
T = PV ÷ nR
But, n, the number of moles = Mass ÷ Molar mass
Molar mass of iodine = 253.8089 g/mol
Thus, n = 0.276 g ÷ 253.8089 g/mol
= 0.001087 moles
Therefore;
T = (0.478 atm × 0.0714 L) ÷ (0.001087 moles × 0.082057)
= 382.63 K
Thus, the temperature of Iodine in Kelvin is 382.63 K
I think it’s A (don’t take my word for it just consider that one greatly)
You multiply the percentage and theoretical yield together.