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vampirchik [111]
3 years ago
13

Let θ be an angle in quadrant IV such that sinθ = -2/5 . Find the exact values of secθ and tanθ.

Mathematics
1 answer:
Gnesinka [82]3 years ago
8 0

If <em>θ</em> lies in the fourth quadrant, then sin(<em>θ</em>) < 0 and cos(<em>θ</em>) > 0. So we have from the Pythagorean identity,

sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1   ==>   cos(<em>θ</em>) = +√(1 - sin²(<em>θ</em>)) = √21/5

Then

sec(<em>θ</em>) = 1/cos(<em>θ</em>) = 5/√21

and

tan(<em>θ</em>) = sin(<em>θ</em>)/cos(<em>θ</em>) = (-2/5)/(√21/5) = -2/√21

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IMAGE PROVIDED.

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