1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vampirchik [111]
3 years ago
13

Let θ be an angle in quadrant IV such that sinθ = -2/5 . Find the exact values of secθ and tanθ.

Mathematics
1 answer:
Gnesinka [82]3 years ago
8 0

If <em>θ</em> lies in the fourth quadrant, then sin(<em>θ</em>) < 0 and cos(<em>θ</em>) > 0. So we have from the Pythagorean identity,

sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1   ==>   cos(<em>θ</em>) = +√(1 - sin²(<em>θ</em>)) = √21/5

Then

sec(<em>θ</em>) = 1/cos(<em>θ</em>) = 5/√21

and

tan(<em>θ</em>) = sin(<em>θ</em>)/cos(<em>θ</em>) = (-2/5)/(√21/5) = -2/√21

You might be interested in
Need help for question 8 and 9. I need the equation that’s passes through the points!
dsp73

Answer:

Step-by-step explanation:

Question 8

Let the equation of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

y = mx + b

Here, m = slope and y-intercept = b

Since, m = \frac{y_2-y_1}{x_2-x_1}

For two points (1, 4) and (5, 8),

m = \frac{8-4}{5-1}

m = 1

Equation will be,

y = (1)x + b

y = x + b

Since, this line passes through (1, 4),

4 = 1 + b

b = 3

Therefore, equation of the line will be,

y = x + 3

Question 9

Let the equation is y = mx + b

m = \frac{y_2-y_1}{x_2-x_1}

For two points (2, 10) and (6, 4)

m = \frac{10-4}{2-6}

m = -\frac{3}{2}

By substituting the value of 'm' in the equation,

y = -\frac{3}{2}x+b

Since, this line passes through (2, 10)

10 = -\frac{3}{2}(2)+b

b = 10 + 2

b = 12

Therefore, equation of the line will be,

y=-\frac{3}{2}x+12

4 0
3 years ago
What are the solution(s) to the quadratic equation 50 – x2 = 0?
Dmitrij [34]

Answer:

x = ±5\sqrt{2}

Step-by-step explanation:

We have been given the quadratic equation;

50-x^{2}=0

The first step is to subtract 50 from both sides of the equation;

50-x^{2}-50=0-50

-x^{2}=-50

Multiplying both sides by -1 yields;

x^{2}=50

The final step is to obtain square roots on both sides;

\sqrt{x^{2} }=\sqrt{50}\\x=+/-\sqrt{50}

Therefore, x = ±5\sqrt{2}

5 0
3 years ago
Could someone pleasee answer this?
Snezhnost [94]

Answer:

Step-by-step explanation:

7 0
3 years ago
Members of the Video Digital club produce short videos. At the end
allsm [11]

Answer:

hggggggggjrhg

Step-by-step explanation:

fhhhhhhhgtrhrehr this is the right answer

5 0
3 years ago
What is the slope of this line?
Dahasolnce [82]
Slope is rise over run. Go up 1 unit, right 4 units to get to the next point.
the slope is 1/4
5 0
3 years ago
Read 2 more answers
Other questions:
  • I need an answer quickly!
    13·1 answer
  • Suppose the roots of the equation 2x^2−5x−6=0 are α and β.Find the quadratic equation with roots 1/α and 1/β.​
    9·1 answer
  • Express 89% as a fraction
    5·1 answer
  • Which of the ordered pairs is<br> 4x – 1= 3y + 5
    11·1 answer
  • PLEASE HELP.Ill mark you brainliest if its right
    10·2 answers
  • 8kg ham costs $12/kg. find the cost per pound.
    7·1 answer
  • HURRY PLEASE I WILL GIVE BRAINLIEST
    6·1 answer
  • The parking lot is 4 km wide. The area of the parking lot is 24 kilometers. What is length of the parking lot?
    14·2 answers
  • What is the mean of the following set of data:<br> {11, 5, 7, 11, 3, 4, 7, 4, 5}
    6·2 answers
  • 12. MP Persevere with Problems Write the function rule for each function.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!