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Soloha48 [4]
3 years ago
13

Polycarbonate plastic has a density of 1.2

Chemistry
1 answer:
lapo4ka [179]3 years ago
3 0

The mass of the photo frame : = 549.12 g

<h3>Further explanation</h3>

Given

a photo frame

two 5.2 mm sheets = 0.52 cm

22 cm by 20 cm dimension

Required

the mass

Solution

The volume of one sheet = l x w x h

= 22 cm x 20 cm x 0.52 cm

= 228.8 cm³

Mass of one sheet :

= density x volume

= 1.2 g/cm³ x 228.8 cm³

= 274.56 g

So for two sheets of polycarbonate :

= 2 x  274.56 g

= 549.12 g

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You're provided a 0.50 M solution of HCl. How many moles of HCl are present in 25 ml of this solution? ​
ddd [48]

Answer:

0.0125 moles of HCl

Explanation:

(0.50 mol/L)(0.025 L) = 0.0125 moles of HCl

4 0
3 years ago
if theres no coefficient on a element symbol, is the power automatically 1 like it would be if there was no subscript?
Ivenika [448]
Yup go this website for more information http://dwb.unl.edu/calculators/activities/BalEqn.html
5 0
3 years ago
a) Whatis the composition in mole fractions of a solution of benzene and toluene that has a vapor pressure of 35 torr at 20 °C?
iogann1982 [59]

Answer:

molar composition for liquid

xb= 0.24

xt=0.76

molar composition for vapor

yb=0.51

yt=0.49

Explanation:

For an ideal solution we can use the Raoult law.

Raoult law: in an ideal liquid solution, the vapor pressure for every component in the solution (partial pressure) is equal to the vapor pressure of every pure component multiple by its molar fraction.  

For toluene and benzene would be:

P_{B}=x_{B}*P_{B}^{o}

P_{T}=x_{T}*P_{T}^{o}

Where:

P_{B} is partial pressure for benzene in the liquid  

x_{B} is benzene molar fraction in the liquid  

P_{B}^{o} vapor pressure for pure benzene.  

The total pressure in the solution is:

P= P_{T}+ P_{B}

And  

1=x_{B}+x_{T}

Working on the equation for total pressure we have:

P=x_{B}*P_{B}^{o} + x_{T}*P_{T}^{o}

Since x_{T}=1-x_{B}

P=x_{B}*P_{B}^{o} + (1-x_{B})*P_{T}^{o}

We know P and both vapor pressures so we can clear x_{B} from the equation.

x_{B}=\frac{P- P_{T}^{o}}{ P_{B}^{o} - P_{T}^{o}}

x_{B}=\frac{35- 22}{75-22} = 0.24

So  

x_{T}=1-0.24 = 0.76

To get the mole fraction for the vapor we know that in the equilibrium:

P_{B}=y_{B}*P

y_{T}=1-y_{B}

So  

y_{B} =\frac{P_{B}}{P}=\frac{ x_{B}*P_{B}^{o}}{P}

y_{B}=\frac{0.24*75}{35}=0.51

y_{T}=1-0.51=0.49

Something that we can see in these compositions is that the liquid is richer in the less volatile compound (toluene) and the vapor in the more volatile compound (benzene). If we take away this vapor from the solution, the solution is going to reach a new state of equilibrium, where more vapor will be produced. This vapor will have a higher molar fraction of the more volatile compound. If we do this a lot of times, we can get a vapor that is almost pure in the more volatile compound. This is principle used in the fractional distillation.

7 0
3 years ago
A molecule has two atoms that are bonded to the central atom and one lone pair of electrons around this central atom. What is th
alex41 [277]
The shape of the molecule is trigonal planar.
For example, H₂O:
     ..
    O
  /    \
H     H

3 0
4 years ago
Read 2 more answers
Out of 500 silicon atoms: 460 are si-28, which has a mass of 27.98 amu 25 are si-29, which has a mass of 28.98 amu and 15 are si
liberstina [14]

Answer;

=28.09 amu

Explanation;

In this problem, they did not give us the percentages. However, since we know the number of atoms, we can easily calculate the percentages. For example:  

(460 X 100)/500 = 92%  

If we do this for all three isotopes,

(460 × 25)/500 = 5 %

(460 × 15) /500 = 3%

-We get 92%, 5%, and 3%. (We'll assume these are absolute numbers for determining our significant figures).

Now the problem is just like the previous one. First convert the percentages into decimals. Then multiply those decimals by the masses and add. Here's the solution:  

= (0.92) X (27.98 amu) + (0.05) X (28.98 amu) + (0.03) X (29.97 amu)

= 25.74 amu  +  1.449 amu  + 0.8991 amu

= 28.09 amu

6 0
3 years ago
Read 2 more answers
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