Answer: decrease the temperature of the reaction
Explanation:
CH3COOH + CH3CH2OH ⇌ CH3COOCH2CH3 + H2O
The formation of an ester is an exothermic reaction. Therefore, a decrease in the temperature of the reaction will favour the production of ester.
Answer:
If the temperature and volume ot a gas increases, the r.m.s. velocity of the molecules in the gas will be 2 times the original r.m.s. molecular velocity.
If T doubles while V is held constant, the new net internal energy of the gas will be 2 times the original internal energy of the gas.
Explanation:
Temperature and root mean square velocity are directly proportional to one anoth. If the temperature increases, root mean square velocity also increases and vice versa, while temperature is also directly proportional to the internal energy of the gas molecules, higher the temperature, higher will be the internal energy and lower the temperature so internal energy will be decreased.
Answer:
to simplify the number by using fewer digits
Explanation:
Answer:
Mass = 1.33 g
Explanation:
Given data:
Mass of argon required = ?
Volume of bulb = 0.745 L
Temperature and pressure = standard
Solution:
We will calculate the number of moles of argon first.
Formula:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
By putting values,
1 atm ×0.745 L = n × 0.0821 atm.L/mol.K× 273.15 K
0.745 atm. L = n × 22.43 atm.L/mol
n = 0.745 atm. L / 22.43 atm.L/mol
n = 0.0332 mol
Mass of argon:
Mass = number of moles × molar mass
Mass = 0.0332 mol × 39.95 g/mol
Mass = 1.33 g
