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3 years ago

5

Which statements are true?

1 answer:

Mashutka [201]3 years ago

6 0

Answer:

It doesn’t necessarily ask for reasoning, but I’ll just say all of the above are correct, the definition of congruent is “identical in form” or the same. A 25 degree angle would be congruent to a 25 degree angle, two intersecting lines form 4 angles or two lines that equal 180 degrees on each side, and both angle pairs of 2 are gonna be congruent to each other respectively, and two congruent angles of 45 degrees would add up to 90 degrees.

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HELP!!! use cross multiplication

Tresset [83]

Let x be the number of square feet to be mowed
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x square feet take 12 minutes

$22x = 12 \times 215 \\ x = (12 \times 215) \div 22$

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3 years ago

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Write the slope-intercept form of the equation of the line satisfying the given conditions through(3,-3); slope=-4

il63 [147K]

Answer:

y=-4x+9

Step-by-step explanation:

y-y1=m(x-x1)

y-(-3)=-4(x-3)

y+3=-4(x-3)

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y=-4x+9

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3 years ago

5/16 as a decimal..?

madam [21]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:

tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

$Q1 = \frac{14}{4}th$

$Q1 = 3.5th$

This is the average of the 3rd and the 4th element

$Q1 = \frac{1}{2} \times (84 + 91)$

$Q1 = 87.5$

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

$Q3 = 3 \times 3.5th$

$Q3 = 10.5th$

This is the average of the 10th and the 11th element.

$Q_3 =\frac12 \times (98 + 101)$

$Q_3 =99.5$

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

$IQR = Q_3 -Q_1$

$IQR = 99.5 - 87.5$

$IQR = 12$

Also, we have:

$IQR(1.5) = 12 \times 1.5$

$IQR(1.5) = 18$

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

$Lower = 87.5- 18$

$Lower = 69.5$

$Upper = Q_3 + IQR(1.5)$

$Upper = 99.5 + 18$

$Upper = 117.5$

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

6 0

2 years ago