Saw the image.
Given:
Whole wall is 13 2/3 ft by 25ft
4 menus (gray areas) with measurements of 6 ft wide and 7 1/2 ft tall.
Convert mixed fractions into improper fractions.
13 2/3 ft = ((13*3)+2)/3 = 41/3
Area of the Wall = 41/3 ft * 25 ft = (41*25)/3 = 1025/3 ft² = 341 2/3 ft²
7 1/2 ft = ((7*2)+1)/2 = 15/2
Area of the menu = 15/2 ft * 6 ft = (15*6)/2 = 90/2 = 45 ft²
45 ft² x 4 menus = 180 ft²
Area of wall space not covered by the chalkboard paint:
A = 341 2/3 ft² - 180 ft² = 161 2/3 ft²
The rule for side lengths of a triangle is that the two lowest lengths sum has to be greater than the longest length. so
a+b>c
For the 1st question
4+3>6
7>6
So yeah, it can be a triangle
For the 2nd one
1+3>4
4>4
So no, it can't be a triangle
Sandy has two possibilities
lengths of 3,3,4
or
lengths of 4,4,3
Answer:
bc
Step-by-step explanation:
Answer:
<h2>Hey option A is correct......</h2>
