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alukav5142 [94]
4 years ago
14

An element with the electron configuration [xe] 6s24f145d7 would belong to which class on the periodic table?

Chemistry
1 answer:
Alinara [238K]4 years ago
8 0
If the atom is neutral then, the total number of electrons is the same as the number of protons. We calculate for the total number of electrons given the compressed electron configuration,
   number of electrons of Xenon (Xe) = 54
The total number of electrons after Xenon,
   = 2 + 14 + 7 = 23

Adding up all the number of electrons, we have,
   total number of electrons = 54 + 23 = 77

The identity of this element is Iridium (Ir). This element belongs to the class of Group 9. This is the transition metal. 
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A and B react together in this reversible reaction. A + 3B --> C + 2D. A mixture of 10 mol of A and 10 mol of B were left to
alexira [117]
Not multiple choice?
4 0
4 years ago
PLEASE HELP!!
NARA [144]
We can skip option B and D because NaCl is salt and H₂SO₄ is a strong acid.
Neutralization reactions are those reactions in which acid and base react to form salt and water.
As water being amphoteric in nature can react with HCl as follow,

                           HCl  +  H₂O   ⇆  H₃O⁺  +  OH⁻

In this case no salt is formed, so we can skip this option.

Ammonia being a weak base can abstract proton from HCl as follow,

                              HCl  +  NH₃  →  NH₄Cl

Ammonium Chloride is a salt. So, among all four options, Option-C is the correct answer.
3 0
3 years ago
Read 2 more answers
What is the frequency of the light with a wavelength of 4.90x10^-7 m
docker41 [41]

Answer: 6.12\times 10^{14} Hz

Explanation: Recall the formula for the speed of light is

c=\lambda v

where c is the speed of light,\lambda is the wavelength, and v is the frequency. Assuming this takes place in a vacuum, c=3.00\times 10^8 m/s. Now we can solve for frequency

c=\lambda v

3.00\times 10^8 = 4.90\times 10^{-7}\cdot v

v = \frac{3.00\times 10^8}{4.90\times 10^{-7}}

v =6.12\times 10^{14} (rounding to 3 sig figs)

Thus, the frequencyis 6.12\times 10^{14} Hz.

6 0
3 years ago
What is the percent by mass (mv) of a solution with 1.56 g of benzene dissolved in gasoline to make 998.44 mL of solution? (dens
Marina CMI [18]

Answer:

The percentage by mass of benzene in the solution is approximately 0.2%

Explanation:

The given parameters are;

The mass of the benzene solute dissolved in the gasoline solvent, m₁ = 1.56 g

The total volume of the benzene gasoline solution made, V = 998.44 mL

The density of gasoline, ρ = 0.7489 g/mL

Mass, m = Density, ρ × Volume, V

∴ The mass of gasoline in the 998.44 mL, solution = 0.7489 g/mL × 998.44 mL = 747.731716 g

The total mass of the solution = The mass of the benzene in the solution + The mass of the gasoline in the solution

∴ The total mass of the solution = 747.731716 g + 1.5 g = 749.231716 g

The \ percentage \  by \  mass = \dfrac{The  \  mass \   of \   a  \  fraction}{(The  \  mass  \  of  \  the  \  total  \  solution)} \times  100

The percentage by mass of benzene in the solution = (1.5 g/749.231716 g)×100 ≈ 0.2% by mass.

6 0
3 years ago
Can u guys please answer this<br><br> What plasma looks like on the molecular level?
meriva
They look like gases plasmas have no fixed shapes or volume and are less dense tan solids or liquids
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3 years ago
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