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LiRa [457]
2 years ago
8

What’s the growth factor of f(x)=500(1+.12)^x

Mathematics
1 answer:
ikadub [295]2 years ago
6 0

Answer:

Step-by-step explanation:

The growth factor is (1 + 0.12), which is the same as 1.12.  

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Use the periodic compound interest formula to solve.
77julia77 [94]

Answer:

$15,539.67

Step-by-step explanation:

Compound Interest Formula

\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}

where:

  • A = final amount
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • P = $11,000
  • r = 5.8% = 0.058
  • n = 4 (quarterly)
  • t = 6 years

Substitute the given values into the formula and solve for A:

\implies \sf A=11000\left(1+\frac{0.058}{4}\right)^{(4 \times 6)}

\implies \sf A=11000(1.0145)^{24}

\implies \sf A=15539.67451...

Therefore, the value of the investment after 6 years will be $15,539.67 to the nearest cent.

3 0
2 years ago
(( I will give 25 points and brainy from right answers (Please answer all!!) )
sleet_krkn [62]
1. C. Concave pentagon

2. A. 1620°

b/c (11 - 2) × 180 = 1620

3. B. 165°

b/c (24 - 2) × 180 ÷ 24 = 165

4. A. 160°

b/c (18 - 2) × 180 ÷ 18 = 160
6 0
3 years ago
Find the absolute maximum and absolute minimum for f (x )equals x cubed minus 2 x squared minus 4 x plus 2 on the interval 0 les
sineoko [7]

9514 1404 393

Answer:

  • maximum: 2
  • minimum: -6

Step-by-step explanation:

The extrema will be at the ends of the interval or at a critical point within the interval.

The derivative of the function is ...

  f'(x) = 3x² -4x -4 = (x -2)(3x +2)

It is zero at x=-2/3 and at x=2. Only the latter critical point is in the interval. Since the leading coefficient of this cubic is positive, the right-most critical point is a local minimum. The coordinates of interest in this interval are ...

  f(0) = 2

  f(2) = ((2 -2)(2) -4)(2) +2 = -8 +2 = -6

  f(3) = ((3 -2)(3) -4)(3) +2 = -3 +2 = -1

The absolute maximum on the interval is f(0) = 2.

The absolute minimum on the interval is f(2) = -6.

8 0
2 years ago
Can anyone explain tonme how to do this please?
Mars2501 [29]
C is right. She has partially completed the construction. Her next step is to use the arc markings to determine the radius to construct the circle.
4 0
3 years ago
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The graph of is shown below. What is the value of y when x = 0?
jarptica [38.1K]

\huge\text{Hey there!}


\huge\textsf{This equation/question should be easy to}\\\\\huge\textsf{to solve for because, we have everything you}\\\\\huge\textsf{you will need on your graph and somewhat in}\\\\\huge\textsf{the question because it already gave you the}\\\\\huge\boxed{\mathsf{x-intercept}}\huge\textsf{.}
\mathsf{y = |x| - 2}

\mathsf{y = |0| - 2}

\mathsf{y = 0 - 2}

\mathsf{y = -2}
\huge\textsf{Therefore, your answer should be: }

\huge\boxed{\mathsf{y= }\frak{\ -2} \ \rm{(Option\ D.)}}\huge\checkmark


\huge\text{Good luck on your assignment \& enjoy your day!}

<h3>
~\frak{Amphitrite1040:)}</h3>
6 0
1 year ago
Read 2 more answers
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