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Answer:
Explanation:
The force that one atom exerts on the other is the negative derivative of the potential energy = 
F(x) = - 
( -C₆ / x⁷) = - (- (-6) C₆ x⁻⁶ ⁻¹) = - 6C₆ /x⁷
when xis negative, F is positive and when x is positive, F is negative. It is therefore and attractive force and F is always directed to the center
Considering north as positive Y axis
First 10 miles north means a positive 10 displacement along y direction
Second 20 miles south means a negative 20 displacement along y direction
Third 5 miles south means a positive 5 displacement along y direction
So total displacement = 10 - 20 + 5 = -5 miles displacement
So position vector of the final position = - 5 j
I found some good web pages with highly detailed answers to predicting the range of a trebuchet. A very simple model we have used in my Intro to Eng class just uses the mass of the projectile (m2), the mass of the counter weight (m1), and the height the counter weight falls (h):
Range (max) = 2 * (m1/m2) * h
Now the efficiency of the trebuchet will cause this model to be off by quite a bit. But once you have a working trebuchet, we find this model works well when we vary m1, m2, or h. We assume we have a take off angle of 45 degrees above the horizon.
This solution is based on the classic max range ballistics problem - 45 degree take off angle. It also assumes converting all the potential energy of the counter weight to kinetic energy of the projectile. That is why the efficiency issue comes up as a lot of energy is lost due to friction in the moving trebuchet. If the projectile spins a lot then it will travel a shorter distance as the potential energy is split into kinetic and rotational energy. Projectile shape and wind will also vary the results.
Good luck.
Answer:
I think the answer is a
Explanation:
This is because the 2 “v” lines are moving parallel to x and to eachother.
