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2 years ago

14

Chris wrote a equation and the first step of his solution process, as shown. what math operation did Chris apply in his first st

ep

1 answer:

Burka [1]2 years ago

8 0

Is there some what picture or graph?

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Enter the simplified form of the complex fraction in the box. Assume no denominator equals zero.

Olenka [21]

Answer:

$\frac{(9-x)}{3x}$

Step-by-step explanation:

we have

$\frac{\frac{2}{x-3}-\frac{3}{x}}{\frac{3}{x-3}}$

step 1

Solve the numerator of the quotient

$\frac{2}{x-3}-\frac{3}{x}=\frac{2x-3(x-3)}{(x-3)x}=\frac{2x-3x+9}{(x-3)x}=\frac{9-x}{(x-3)x}$

step 2

substitute in the original expression

$\frac{\frac{9-x}{(x-3)x}}{\frac{3}{x-3}}$

$\frac{(x-3)(9-x)}{3x(x-3)}$

step 3

simplify

$\frac{(9-x)}{3x}$

5 0

2 years ago

F(x) = 2x² + 2, find f(5).?

Romashka-Z-Leto [24]

Answer:

sorry if i got it wrong but i think its 22 if f5

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Solve for x: 4 over x equals 5 over 10

julsineya [31]

Answer:

x = 8,

Step-by-step explanation:

$\displaystyle \frac{4}{x} = \frac{5}{10}$ .

$x \ne 0$ for it is a denominator. Multiply both sides with the product of the two denominators: $10\;x$ :

$\displaystyle \frac{4}{x}\cdot (10\; x) = \frac{5}{10}\cdot (10\;x)$ .

$40 = 5\; x$ .

Multiply both sides by one over the coefficient of x:

$\displaystyle \frac{1}{5} \times 40 = \frac{1}{5}\times 5\; x$ .

$x = 8$ .

8 0

3 years ago

Read 2 more answers

There are 72 packs of sugar in a box. Each sugar pack is 9/10 of an ounce. How many ounces are in a box?

mixas84 [53]

9/10 of an ounce is 0.9. 0.9 X 72 = 64.8.

There is 64.8 ounces in a box.

7 0

3 years ago

Which function grows at the fastest rate for increasing values of x? g(x)=14x p(x)=12x3+9 f(x)=2x2−x h(x)=3x

iris [78.8K]

The function that is growing at the fastest rate is p(x) = 12x^3 + 9.

This is a cubic function, meaning that x is raised to the third power. This is the only function that is raised to the third power, so it will increase the fastest.

5 0

3 years ago