The answer to the question is
<span>PE = W = 1/2 (kx^2)
16.2 = </span>1/2 (k(0.30)^2)
k = 360 J/m^2
Answer:
t = 123.59s
Explanation:
For the launch pad section:
Vf = Vo + a*t where Vo=0.
Vf = 35*25 = 875m/s
The distance traveled during the launch:
Now the projectile motion, we know that its initial speed is the speed calculated previously and the initial height is the y-component of the previously calculated distance.
where d= 10937.5m; Vo=875m/s.
Solving for t:
t1 = -11.093s t2 = 98.59s
So, the total time of flight will be:
The three parts of the ear anatomy are the outer ear, the middle ear
and the inner ear. The inner ear is also called the cochlea. (‘Cochlea’
means ‘snail’ in Latin; the cochlea gets its name from its distinctive
coiled up shape.)
The outer ear consists of the pinna, ear canal and eardrum
The middle ear consists of the ossicles (malleus, incus, stapes) and ear drum
The inner ear consists of the cochlea, the auditory (hearing) nerve and the brain
Sound waves enter the ear canal and make the ear drum vibrate. This
action moves the tiny chain of bones (ossicles – malleus, incus, stapes)
in the middle ear. The last bone in this chain ‘knocks’ on the membrane
window of the cochlea and makes the fluid in the cochlea move. The
fluid movement then triggers a response in the hearing nerve.
or
<span>Sound waves enter the ear canal and make the ear drum vibrate. This action moves the tiny chain of bones (ossicles – malleus, incus, stapes) in the middle ear. The last bone in this chain 'knocks' on the membrane window of the cochlea and makes the fluid in the cochlea move.
please mark me as brainliest!!
</span>
Answer:
337k
Explanation:
First, let us find the difference between the given two temperatures.
Difference = 85°C - 21°C
= 64°C
<u>And now we have to write the temperature in kelvins.</u>
To convert Celcius to Kelvins you can add 273 to the temperature in Celcius.
<u>Let us find it now.</u>
64°C + 273 = 337k
Therefore,
64°C ⇒ <u>337k</u>
Answer:
2500 and kg its is very easy do with method
