Answer:
- The procedure is: solve the quadratic equation for
.
Explanation:
This question assumes uniformly accelerated motion, for which the distance d a particle travels in time t is given by the general equation:
That is a quadratic equation, where the independent variable is the time .
Thus, the procedure that will find the time t at which the distance value is known to be D is to solve the quadratic equation for .
To solve it you start by changing the equation to the general form of the quadratic equations, rearranging the terms:
Some times that equation may be solved by factoring, and always it can be solved by using the quadratic formula:
Where:
That may have two solutions. Some times one of the solution makes no physical sense (for example time cannot be negative) but others the two solutions are valid.
Answer: 8 or 9
Explanation: they are so many ocean water in the world
Answer:
longitudinal engineering strain = 624.16
true strain is 6.44
Explanation:
given data
diameter d1 = 0.5 mm
diameter d2 = 25 mm
to find out
longitudinal engineering and true strains
solution
we know both the volume is same
so
volume 1 = volume 2
A×L(1) = A×L(2)
( π/4 × d1² )×L(1) = ( π/4 × d2² )×L(2)
( π/4 × 0.5² )×L(1) = ( π/4 × 25² )×L(2)
0.1963 ×L(1) = 122.71 ×L(2)
L(1) / L(2) = 122.71 / 0.1963 = 625.16
and we know longitudinal engineering strain is
longitudinal engineering strain = L(1) / L(2) - 1
longitudinal engineering strain = 625.16 - 1
longitudinal engineering strain = 624.16
and
true strain is
true strain = ln ( L(1) / L(2))
true strain = ln ( 625.16)
true strain is 6.44
Missing detail in the text: total voltage of the circuit
Missing figure: https://www.physicsforums.com/attachments/prob-24-68-jpg.190851/
Solution:
1) The energy stored in a circuit of capacitors is given by
where
is the equivalent capacitance of the circuit. We can find the value for
by using
and the energy of the system,
2) Then, let's calculate the equivalente capacitance of C1 and C2. The two capacitors are in series, so their equivalente capacitance is given by
from which we find
3) Then let's find
, the equivalent capacitance of
and C3.
is in series with C4, therefore we can write
Since we already know
and
, we find
4) Finally, we can find
, because it is in parallel with
, and the equivalent capacitance of the two must be equal to
:
So, using
and
, we find
Answer:
the fundamental resonant frequency is 95.76 Hz
Explanation:
The computation of the fundamental resonant frequency be is given below:
= 1.34 m - 0.442 m
= 0.898 m
Now
Now the fundamental resonant frequency is
= 95.76 Hz
hence, the fundamental resonant frequency is 95.76 Hz
