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Law Incorporation [45]
3 years ago
6

When two objects are near each other, how would increasing one object’s mass affect it?

Physics
2 answers:
worty [1.4K]3 years ago
8 0

Answer:

b

Explanation

np

Otrada [13]3 years ago
8 0
I would have to say
A)
Hopefully this helped
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If you were to drive to some city south of your current location, how would the altitude of the celestial pole in the sky change
aleksandrvk [35]

Answer:

For northern hemisphere, the altitude will decrease. For southern hemisphere, the altitude will increase

Explanation:

Because of the spherical shape of the Earth the altitude (separation from the horizon in degrees) of the celestial pole changes as per the latitude of the place. The altitude of the celestial pole is equal to the latitude of the observer.

If the observer is in the northern hemisphere and moves south the altitude of the celestial pole will decrease.

If the observer is in the southern hemisphere and moves south the altitude of the celestial pole will increase.

4 0
3 years ago
A fighter pilot experiences a force of 1000N to the west. If his mass is 70kg, what is his acceleration ​
lana66690 [7]

Acc = 1000 / 70 = 14.29 m/s^2

5 0
4 years ago
Read 2 more answers
What is the net force necessary for a 1.6 x 103 kg car to accelerate forward at 2.0<br> m/s?
erastova [34]

Answer:31245.132

Explanation:

yeah

8 0
4 years ago
What is 60mph (miles per hour) in meters per second? ( A mile is 5280ft)<br> please someone help me
777dan777 [17]

Answer:

60mph=26.8224meters per second

Explanation:

4 0
3 years ago
While goofing off at the ice skating rink, a student takes off her shoes and places each of them on the ice. Her friend, a hocke
sukhopar [10]

Answer:

Right shoe

Explanation:

Let the mass and velocity of incoming puck be m and v respectively.

Momentum of the colliding puck will be mv

In case of first case , the momentum of puck becomes zero so change in momentum after collision with left shoe

= mv - 0 = mv

If time duration of collision be t

rate of change of momentum

= mv / t

This is the force exerted by puck on the left shoe .

Now let us consider collision with right shoe

momentum after collision with right  shoe

- mv

change in momentum

= mv - ( - mv ) = 2mv

If time duration of collision be t

rate of change of momentum

= 2mv / t

This is the force exerted by puck on the right  shoe .

Since the force on the right shoe is more , this shoe will have greater speed

after collision.

6 0
3 years ago
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