Answer:
The acceleration of man 1 and 2 is and
.
Explanation:
Mass of man 1, m₁ = 80 kg
Mass of man 2, m₂ = 60 kg
One man pulls on the rope with a force of 250 N.
Let a₁ is acceleration of man 1,
F = m₁a₁
Let a₂ is acceleration of man 1,
F = m₂a₂
So, the acceleration of man 1 and 2 is and
.
Answer: hello some part of your question is missing attached below is the missing detail
answer :
<em>w</em>f = M( v cos∅ )D / I
Explanation:
The Angular speed <em>wf </em>of the system after collision in terms of the system parameters and I can be expressed as
considering angular momentum conservation
Li = Lf
M( v cos∅ ) D = ( ML^2 / 3 + mD^2 ) <em>w</em>f
where ; ( ML^2 / 3 + mD^2 ) = I ( Inertia )
In terms of system parameters and I
<em>w</em>f = M( v cos∅ )D / I
