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Dmitrij [34]
3 years ago
13

Is it possible to add three vectors of equal magnitude but a different direction to get a null vector?

Physics
1 answer:
Sauron [17]3 years ago
5 0

Answer:

Yes, it is possible to add three vectors of equal magnitudes and get zero. This can happen if the resultant of the two vectors are equal and opposite in direction to the third vector.

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An element can be identified by its spectrum. True False
ivann1987 [24]
<span>True. Even though some elements have very similar spectrums that are not easy to tell apart so need to be examined carefully.</span>
4 0
3 years ago
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The following quantities describe location or its change:position, distance, and a displacement. Which are vectors?
-Dominant- [34]

As per the question there are three physical quantities named as position,distance and displacement.

Before coming into a conclusion first we have to understand a vector and a scalar.

A scalar quantity is a quantity which has only magnitude for it's complete specifications.

A vector is a quantity which has magnitude as well as direction and at the same time it is in accordance with the paraellogram law of vector addition.

Out of the three options displacement and position are vector quantities.It is because it is the minimum distance between two points .It has magnitude as well as direction.

Distance can not be considered as a vector quantity as it has only magnitude.There is no specific directions of distance travelled.

Position vector is a vector which provides location of an object in a plane or space.It is nothing else except the point which has x,y,z coordinates with origin is taken as the reference point.

Hence position and displacement are vectors

6 0
3 years ago
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Force F = (-6.0 N)ihat + (2.0 N) jhatacts on a particle with position vector r =(4.0 m) ihat+ (4.0 m) jhat.
finlep [7]

Answer:

\tau=(-32k)\ N-m

\theta=116.55^{\circ}

Explanation:

Given that.

Force acting on the particle, F=(-6i + 2.0j)\ N

Position of the particle, r=(4i+4j)\ m

To find,

(a) Torque on the particle about the origin.

(b) The angle between the directions of r and F

Solution,

(a) Torque acting on the particle is a scalar quantity. It is given by the cross product of force and position. It is given by :

\tau=F\times r

\tau=(-6i + 2.0j)\times (4i+4j)

\tau=\begin{pmatrix}0&0&-32\end{pmatrix}

\tau=(-32k)\ N-m

So, the torque on the particle about the origin is (32 N-m).

(b) Magnitude of r, |r|=\sqrt{4^2+4^2}=5.65\ m

Magnitude of F, |F|=\sqrt{(-6)^2+2^2}=6.324\ m

Using dot product formula,

F{\circ}\ r=|F|.|r|\ cos\theta

cos\theta=\dfrac{F{\circ} r}{|F|.|r|}

cos\theta=\dfrac{-24+8}{6.324\times 5.65}

\theta=116.55^{\circ}

Therefore, this is the required solution.

6 0
2 years ago
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Technician a says multiple discharge ignition system fires the spark plug during each of the engine's four cycle strokes. Techni
patriot [66]

Answer:

Technician B only is correct

Explanation:

Here we have that the multiple discharge ignition system is a system that fires the spark plug multiple times during each power stroke to provide ample spark to complete the ignition. Therefore,  technician A is not correct.

The dual spark plug ignition system is a method if obtaining the ideal combustion and improved fuel consumption than a single spark plug ignition system.

Therefore, only technician B is correct.

7 0
3 years ago
When a +0.00235 C charge
irakobra [83]

Answer:177.87

Explanation:

4 0
2 years ago
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