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3 years ago

Find JL if JK=17-x, KL=2x-16, and K is the midpoint if JL

Mathematics

1 answer:

Vlada [557]3 years ago

3 0

$JL=JK+KL\\
JL=17-x+2x-16\\
JL=x+1$

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ASHA 777 [7]

Answer:

12 D. Is the answer

Step-by-step explanation:

The equation we will use is

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3 years ago

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3 years ago

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konstantin123 [22]

Answer:

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Step-by-step explanation:

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we put in any value of f(x) and the corresponding value for x to find a value

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but

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3 years ago

Graph the line with slope -3 passing through the point (3,-4)

Vinvika [58]

Given: $\textsf{Slope = -3, Passes through (3, -4)}$

Find: $\textsf{Equation in slope-intercept form}$

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Plug in the values

$y - y_1 = m(x - x_1)$

$y - (-4) = -3(x - 3)$

Distribute

$y + 4 = (-3 * x) + (-3 * - 3)$

$y + 4 = -3x + 9$

Subtract 4 from both sides

$y + 4 - 4 = -3x + 9 - 4$

$y = -3x + 9 - 4$

$y = -3x + 5$

Therefore, after plugging in the values and completing the rest of the steps we were able to determine that equation of the data provided would be $y = -3x + 5$ .

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1 year ago

Factorize 2^x+7 + 2^x+6

joja [24]

Answer:

Step-by-step explanation:

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2 years ago