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Eduardwww [97]
3 years ago
7

Find JL if JK=17-x, KL=2x-16, and K is the midpoint if JL

Mathematics
1 answer:
Vlada [557]3 years ago
3 0
JL=JK+KL\\
JL=17-x+2x-16\\
JL=x+1
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Is it a picture or an answer or something

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3 years ago
Help with math please! This is table to linear equation (level 3)
kolbaska11 [484]

Answer:

y = -5x-4

Step-by-step explanation:

start with slope-intercept form:

-9-11/1+3 = -20/4 = -5

your slope is -5

next, do point-slope form:

y+9 = -5(x-1)

y+9 = -5x+5

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4 0
3 years ago
Slope =<br> ; y-intercept = -3
Goshia [24]

Question is incomplete Let assume the Slope = 2

Answer:

Therefore the Equation of line is

y=2x -3

Step-by-step explanation:

Given:

Slope = 2 ( Assumption )

y-intercept = -3

To Find:

Equation of Line in Slope-intercept form

Solution:

Equation of Line in Slope-intercept Form is given as

y=mx+c

Where,

m=Slope\\c=y-intercept

So, substituting Slope =2 and y-intercept = -3 in above we get

y=2\times x -3 Which is the Required Equation of line

Therefore the Equation of line is

y=2x -3

8 0
3 years ago
Yeah i dont understand this-
Katyanochek1 [597]
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7 0
3 years ago
Read 2 more answers
5. Solve the equation z^2 + 4z - 9 = 0 by completing the square.
Luba_88 [7]

Answer:

A. Z = 2 + N13

Step-by-step explanation:

Let's solve your equation step-by-step.

0=z2+4z−9

Step 1: Subtract z^2+4z-9 from both sides.

0−(z2+4z−9)=z2+4z−9−(z2+4z−9)

−z2−4z+9=0

For this equation: a=-1, b=-4, c=9

−1z2+−4z+9=0

Step 2: Use quadratic formula with a=-1, b=-4, c=9.

z=

−b±√b2−4ac

2a

z=

−(−4)±√(−4)2−4(−1)(9)

2(−1)

z=

4±√52

−2

z=−2−√13 or z=−2+√13

8 0
3 years ago
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