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drek231 [11]
3 years ago
14

PLEASE HELP ASAP I'LL GIVE BRAINLY!!

Physics
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:   b or c

Explanation:  on khan academy

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Which type of wave results from a moderately sloping coastal region?
Naddik [55]

Hey there!

Your answer: Spilling breaker

Spilling breaker usually occurs when a beach or ocean is flat, and as the waves of the wind continues to happen, slowly the region would eventually become a slope.

It's almost like play-dough. Let's say that we set a perfect flat surface of play-dough on the table. As we continue slide our hands one direction, doesn't the play dough have more on one side than the other? It eventually contains a slope if you add enough from the first place.

Your answer: Spilling breaker

8 0
3 years ago
Read 2 more answers
What is the net charge of a copper atom if it gains 2 electrons?
Alex_Xolod [135]
If an atom gains electrons, it develops a negative charge equal to the number of electrons gained.
So the net charge on the copper atom which gained 2 electrons will be -2.
7 0
3 years ago
Por una resistencia de 10 Ω fluyen 5A. ¿Cuál será la diferencia de potencial que se le debe aplicar a la resistencia?
ra1l [238]

Answer:

V = 50 volts

Explanation:

Given that,

Resistance, R = 10 ohms

Current, I = 5 A

We need to find the potential difference across the circuit. We know that,

V = IR

Put all the values,

V = 5 × 10

V = 50 volts

Hence, the potential difference is equal to 50 volts.

8 0
3 years ago
You build a grandfather clock, whose timing is based on a pendulum. You measure its period to be 2s on Earth. You then travel wi
Elenna [48]

Answer:

\frac{g_{2}}{g_{1}} = \frac{1}{4}

Explanation:

The period of the simple pendulum is:

T = 2\pi\cdot \sqrt{\frac{l}{g} }

Where:

l - Cord length, in m.

g - Gravity constant, in \frac{m}{s^{2}}.

Given that the same pendulum is test on each planet, the following relation is formed:

T_{1}^{2}\cdot g_{1} = T_{2}^{2}\cdot g_{2}

The ratio of the gravitational constant on planet CornTeen to the gravitational constant on planet Earth is:

\frac{g_{2}}{g_{1}} = \left(\frac{T_{1}}{T_{2}} \right)^{2}

\frac{g_{2}}{g_{1}} = \left(\frac{2\,s}{4\,s} \right)^{2}

\frac{g_{2}}{g_{1}} = \frac{1}{4}

5 0
3 years ago
Help on matching please, struggling on it. Even just 1 or 2 would help
n200080 [17]

Answer:

7. free fall -- h. 9.8m/s^2

3. Velocity -- x. 60 km/hr west

6. Acceleration -- d. change in velocity/time

8. Centrifugal --  s. towards the centre

13. Work done --w. Force * displacement

5. Uniform circular motion --j. spin cycle in washer

18. Power -- r. kW an hour

7. g -- a. 10N

hope this helps

6 0
2 years ago
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